Apologies for not being clearer. The code does what I want, but I was wondering if there is a simpler way of doing this, using substitute()/bquote() directly without the mapply().
Best, Wolfgang -----Original Message----- From: peter dalgaard [mailto:pda...@gmail.com] Sent: Tuesday, 26 March, 2019 14:42 To: Viechtbauer, Wolfgang (SP) Cc: r-help mailing list Subject: Re: [R] Substitution in expressions Er, I'm confused. You post some code, the code does something. In which sense is this not what you want? This is slightly more direct: > mapply(function(x,y) as.expression(bquote(.(x)^.(y))), base, expo) expression(1L^2, 2L^2, 3L^3, 4L^3, 5L^4) but I sense that you are looking for something else? -pd > On 26 Mar 2019, at 14:27 , Viechtbauer, Wolfgang (SP) > <wolfgang.viechtba...@maastrichtuniversity.nl> wrote: > > Hi All, > > I am trying to create a vector of expressions, where the elements in the > expressions are contained in other vectors (i.e., they should be > substituted). I made some attempts with substitute() and bquote(), but > couldn't get this to work. My solution so far is: > > base <- 1:5 > expo <- c(2,2,3,3,4) > exvec <- as.expression(unname(mapply(function(x,y) bquote(.(x)^.(y)), base, > expo))) > > plot(NA, NA, xlim=c(0,6), ylim=c(0,2)) > text(1:5, 1, exvec) > > Any ideas how I could get this to work with substitute() and/or bquote()? > > Best, > Wolfgang ______________________________________________ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
