Hi Isaac, I am sure you will get lots of answers to this. Here is one using the dplyr package. Assuming that your data frame is called 'a', then library(dplyr) b <- dplyr::group_by(a,plot) %>% dplyr::summarise( mean(lai) ) b # A tibble: 4 x 2 plot `mean(lai)` <int> <dbl> 1 104 243. 2 105 212. 3 106 223. 4 108 212
HTH, Eric On Thu, Feb 14, 2019 at 6:20 PM Isaac Barnhart <i...@ksu.edu> wrote: > I am having trouble finding the mean of a specific part of my dataset. > Here is a sample of it: > > plot lai leaf > 1 104 82 1 > 2 104 167 2 > 3 104 248 3 > 4 104 343 4 > 5 104 377 5 > 6 105 64 1 > 7 105 139 2 > 8 105 211 3 > 9 105 296 4 > 10 105 348 5 > 11 106 94 1 > 12 106 167 2 > 13 106 243 3 > 14 106 281 4 > 15 106 332 5 > 16 108 83 1 > 17 108 382 2 > 18 108 320 3 > 19 108 146 4 > 20 108 129 5 > > I have many different plot numbers, none of which follow any kind of > specific numeric sequence (even though I have sorted them from smallest to > largest). I need to take the average (mean) of the LAI for each plot, and > was wondering if there was a way to specify the code to do this. For > example: I need the average of all the LAI measurements for each leaf of > plot 104, 105, etc. Any help would be appreciated. Thanks! > > Get Outlook for iOS<https://aka.ms/o0ukef> > > [[alternative HTML version deleted]] > > ______________________________________________ > R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
