Hi Dagmar, This will probably involve creating a variable to differentiate the two days in each data.frame:
myframe$day<-as.Date(as.character(myframe$Timestamp),"%d.%m.%Y %H:%M:%S") days<-unique(myframe$day) Then just sample the two subsets and concatenate them: myframe[c(sample(which(myframe$day==days[1]),2), sample(which(myframe$day==days[2]),2)),] Jim On Fri, Dec 7, 2018 at 8:08 PM Dagmar Cimiotti <dagmar.cimio...@ftz-west.uni-kiel.de> wrote: > > Dear all, > > I have data from a time span like this: > > myframe <- data.frame (Timestamp=c("24.09.2012 09:00:00", "24.09.2012 > 10:00:00","25.09.2012 09:00:00", > "25.09.2012 09:00:00","24.09.2012 > 09:00:00", "24.09.2012 10:00:00"), > Event=c(50,60,30,40,42,54) ) > myframe > > > I want to create a new dataframe which includes in this example the data from > two successive days (in my real data I have a big time span and want data > from 25 consecutive days). I understand that I can do a simple sample like > this > > mysample <- myframe[sample(1:nrow(myframe), 4,replace=FALSE),] > mysample > > But I need the data from consecutive days in my random sample. Can anyone > help me with this? > > > Many thanks in advance, > Dagmar > > ______________________________________________ > R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. ______________________________________________ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.