"Why it is setting all row values NA?"
Because the row index is NA. e.g.
> z <- data.frame(a=letters[1:3],b = 1:3); x <- c(TRUE,NA,FALSE)
> z[x,]
a b
1 a 1
NA <NA> NA
Change your logical comparison to (using with() to simplify entry):
> dfc[with(dfc, diff > 0 & diff < 100 | is.na(diff)), ]
week v1 v2 diff
2 w1 NA 42 NA
3 w1 31 32 1
4 w2 31 52 21
5 w2 41 NA NA
6 w3 51 82 31
7 w2 11 22 11
8 w3 11 12 1
10 w1 31 72 41
Cheers,
Bert
On Wed, Sep 12, 2018 at 1:39 PM Val <valkr...@gmail.com> wrote:
>
> I have a data
> dfc <- read.table( text= 'week v1 v2
> w1 11 11
> w1 . 42
> w1 31 32
> w2 31 52
> w2 41 .
> w3 51 82
> w2 11 22
> w3 11 12
> w4 21 202
> w1 31 72
> w2 71 52', header = TRUE, as.is = TRUE, na.strings=c("",".","NA") )
>
> I want to create this new variable diff = v2-v1 and remove rows based
> on this "diff" value as shown below.
> dfc$diff <- dfc$v2 - dfc$v1
> I want to remove row values <=0 and any value greater than >=
> 100 and keep all values including NAs
> dfca <- dfc[((dfc$diff) > 0) & ((dfc$diff) < 100), ]
>
> However, the result is not what I wanted. I want the output as follow,
> week v1 v2 diff
> w1 NA 42 NA
> w1 31 32 1
> w2 31 52 21
> w2 41 NA NA
> w3 51 82 31
> w2 11 22 11
> w3 11 12 1
> w1 31 72 41
>
> However, I got this,l. Why it is setting all row values NA?
> week v1 v2 diff
> <NA> NA NA NA
> w1 31 32 1
> w2 31 52 21
> <NA> NA NA NA
> w3 51 82 31
> w2 11 22 11
> w3 11 12 1
> w1 31 72 41
>
> Any help ?
> Thank you.
>
> ______________________________________________
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> and provide commented, minimal, self-contained, reproducible code.
______________________________________________
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
