your.number=15000
your.denominator=5
your.favorite.n=9
your.vector=NULL
for(i in 0:your.favorite.n){
your.vector[i+1]=your.number/your.denominator^i
your.vector[your.favorite.n+1]=0
}
your.vector ##check
Best,
Daniel
-------------------------
cuncta stricte discussurus
-------------------------
-----Ursprüngliche Nachricht-----
Von: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] Im
Auftrag von Anne-Marie Ternes
Gesendet: Wednesday, July 09, 2008 5:40 AM
An: r-help@r-project.org
Betreff: [R] recursively divide a value to get a sequence
Hi,
if given the value of, say, 15000, I would like to be able to divide that
value recursively by, say, 5, and to get a vector of a determined length,
say 9, the last value being (set to) zero- i.e. like this:
15000 3000 600 120 24 4.8 0.96 0.192 0
These are in fact concentration values from an experiment. For my script, I
get only the starting value (here 15000), and the factor by which
concentration is divided for each well, the last one having, by definition,
no antagonist at all.
I have tried to use "seq", but it can "only" do positive or negative
increment. I didn't either find a way with "rep", "sweep" etc. These
function normally start from an existing vector, which is not the case here,
I have only got a single value to start with.
I suppose I could do something "loopy", but I'm sure there is a better way
to do it.
Thanks a lot for your help, hope the question is not too dumb...
Anne-Marie
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and provide commented, minimal, self-contained, reproducible code.
