grep("(^| )ABHD14A( ;|$)",xgen, value = TRUE)
maybe.
On Mon, Jul 16, 2018 at 1:46 PM, Brian Smith <bsmith030...@gmail.com> wrote:
> Hi,
>
> I was trying to find a pattern ("ABHD14A") in a character string ('xgen' in
> example below) using grepl. Note that the individual members may be
> separated by a semi-colon.
>
> The correct answer should return:
>
> "ABHD-ACY1 ; ABHD14A" "ABHD14A ; YYY"
>
> I have tried three approaches, but still seem a bit off. Attempt 2 below
> gets closest, but it also returns a hit where my pattern is a substring.
> Here is my code:
>
> ===========
>
>
> xgen <- c("XYZ","ABHD-ACY1 ; ABHD14A","ABHD14AXX","ABHD14A ; YYY")
> ga <- "ABHD14A"
>
> # 1.
> kx <- grepl(paste0("^",ga,"$"),xgen)
> xgen[kx]
>
> # 2.
> ky <- grepl(ga,xgen)
> xgen[ky]
>
>
> ==============
>
> What do I need to add/change in #2 above?
>
> many thanks!
>
> [[alternative HTML version deleted]]
>
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