I'm trying to use the IAPWS95 package with the tidyverse packages. For some reason, the function is not outputting the correct rho.
A minimal example with results is below. I've also included the definition of the DTp function from the IAPWS95 library. ==================================== library(IAPWS95) library(tidyverse) initial <- data.frame(T=c(279,294),p=c(0.46,0.46)) initial2 <- initial %>% mutate(rho=DTp(T,p)) > DTp function (T, p) { y <- 0 icode <- 0 res <- .Fortran("DTp", as.double(T), as.double(p), as.double(y), as.integer(icode)) options(digits = 9) if (res[[4]] != 0) { error <- as.character(errorCodes[which(errorCodes[, 1] == res[[4]]), 2]) print(error) } print(res[[3]]) } <bytecode: 0x0000000006f520e0> <environment: namespace:IAPWS95> Results: > initial2 T p rho 1 279 0.46 1000.12283 2 294 0.46 1000.12283 What the results should be: > initial2 T p rho 1 279 0.46 1000.12283 2 294 0.46 998.19167 I think something is evaluating incorrectly, but I don't know enough about NSE vs SE to figure this out. Any thoughts to what could be the reason why the second row has the same rho as the first? When I run the function DTp individually, I get the right results. Shawn Way ______________________________________________ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.