Hi,
My example code is this;
x11<-data.frame(A=c(.6,.6,.6),B=c(.20,.20,.20),C=c(0.20,.20,.20))
ggtern(data=x11,aes(A,B,C,xend = c(0.7,.00,0.7),yend = c(.30,.50,.0),zend
=c(.0,.50,0.3)))+
geom_point()+
theme_showarrows()+geom_segment(size=.5)+
geom_text_viewport(x=c(.45,.27,.37),y=c(.32,.29,.22),label=as.expression("P_a","P_b","P_c"))
ggtern(data=x11,aes(A,B,C,xend = c(0.7,.00,0.7),yend = c(.30,.50,.0),zend
=c(.0,.50,0.3)))+
geom_point()+
theme_showarrows()+geom_segment(size=.5)+
geom_text_viewport(x=c(.45,.27,.37),y=c(.32,.29,.22),label=as.expression(quote(c("P_a","P_b","P_c"))))
In geom_text_viewport (I also tried geom_label and geom_text versions) tried
all possible solutions, but i couldn't achieved. R command outputs are like
this:
Error in stats::complete.cases(df[, vars, drop = FALSE]) :
invalid 'type' (expression) of argument
Maybe i am writing the code wrong, i couldn't figure out.
Thanks for your kind answers.
________________________________________
Kimden: Martin Maechler [maech...@stat.math.ethz.ch]
Gönderildi: 04 Aralık 2017 Pazartesi 16:16
Kime: peter dalgaard
Bilgi: Levent TERLEMEZ; R-help@r-project.org
Konu: Re: [R] ggtern and bquote...
>>>>> peter dalgaard <pda...@gmail.com>
>>>>> on Mon, 4 Dec 2017 14:55:19 +0100 writes:
>> On 4 Dec 2017, at 11:58 , Levent TERLEMEZ via R-help
>> <r-help@r-project.org> wrote:
>>
>> Dear Users,
>>
>> What is the proper way to write symbol, superscript,
>> subscript in ggtern/ggplot? I tried every given example,
>> every possible features of ggplot but couldn’t achived. I
>> just want to write P_a, sigma^2, etc, would you please
>> advise me about this problem.
> Did you try expression(P_a)? I don't do much gg-stuff, but
> I seem to recall that quote() doesn't quite cut it the way
> it does in base graphics.
> -pd
Yes, I vaguely remember that indeed also for the lattice package
(which is based on 'grid' the same as 'ggplot2' is ..) sometimes
expressions instead of calls are needed, i.e., expression(*)
instead of just quote(*).
However, I think Levent really meant what you'd get by
expression(P[a]) ?
@Levent: The clue is the need for valid R syntax, and indeed, as
in LaTeX x_i often is the i-th element of x, the R syntax for
indexing/subsetting is used here, i.e.
x[i] for LaTeX x_i
Last but not least, if Levent really needs bquote() [i.e. substitute()]
then, a final
as.expression(.)
may be needed :
identical(as.expression(quote(a == 1)),
expression( a == 1)) # --> TRUE
--
Martin Maechler, ETH Zurich
________________________________
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