Inline.
-- Bert
On Wed, Nov 22, 2017 at 11:52 PM, Massimo Bressan <
massimo.bres...@arpa.veneto.it> wrote:
> yes, it works, even if I do not really get how and why it's working the
> combination of logical results (could you provide some insights for that?)
>
Read the docs!
?"!"
?NA
explain
Then a more "compact" (but probably less efficient) solution just loops
over the indices:
##UNTESTED
choices <- ***column numbers of _flag columns***
chng <- ***column numbers of columns that will have values changed to NA***
for(i in seq_along choices) mydf[, ] <- is.na(mydf[, chng[i]) <- !mydf[,
choices[i]]
>
> moreover, and most of all, I was hoping for a compact solution because I
> need to deal with MANY columns (more than 40) in data frame with the same
> basic structure as the simplified example I posted
>
> thanks
>
> m
>
>
> ----- Messaggio originale -----
> Da: "Bert Gunter" <bgunter.4...@gmail.com>
> A: "Massimo Bressan" <massimo.bres...@arpa.veneto.it>
> Cc: "r-help" <r-help@r-project.org>
> Inviato: Mercoledì, 22 novembre 2017 17:32:33
> Oggetto: Re: [R] assign NA to rows by test on multiple columns of a data
> frame
>
> Do you mean like this:
>
> mydf <- within(mydf, {
> is.na(A)<- !A_flag
> is.na(B)<- !B_flag
> }
> )
>
> > mydf
> A A_flag B B_flag
> 1 8 10 5 12
> 2 NA 0 6 9
> 3 10 1 NA 0
> 4 NA 0 1 5
> 5 5 2 NA 0
>
>
> Cheers,
> Bert
>
>
> Bert Gunter
>
> "The trouble with having an open mind is that people keep coming along and
> sticking things into it."
> -- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
>
> On Wed, Nov 22, 2017 at 2:34 AM, Massimo Bressan <
> massimo.bres...@arpa.veneto.it> wrote:
>
> >
> >
> > Given this data frame (a simplified, essential reproducible example)
> >
> >
> >
> >
> > A<-c(8,7,10,1,5)
> >
> > A_flag<-c(10,0,1,0,2)
> >
> > B<-c(5,6,2,1,0)
> >
> > B_flag<-c(12,9,0,5,0)
> >
> >
> >
> >
> > mydf<-data.frame(A, A_flag, B, B_flag)
> >
> >
> >
> >
> > # this is my initial df
> >
> > mydf
> >
> >
> >
> >
> > I want to get to this final situation
> >
> >
> >
> >
> > i<-which(mydf$A_flag==0)
> >
> > mydf$A[i]<-NA
> >
> >
> >
> >
> > ii<-which(mydf$B_flag==0)
> >
> > mydf$B[ii]<-NA
> >
> >
> >
> >
> > # this is my final df
> >
> > mydf
> >
> >
> >
> >
> > By considering that I have to perform this task in a data frame with many
> > columns I’m wondering if there is a compact and effective way to get the
> > final result with just one ‘sweep’ of the dataframe?
> >
> >
> >
> >
> > I was thinking to the function apply or lapply but I can not properly
> > conceive how to…
> >
> >
> >
> >
> > any hint for that?
> >
> > [[alternative HTML version deleted]]
> >
> > ______________________________________________
> > R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
> > https://stat.ethz.ch/mailman/listinfo/r-help
> > PLEASE do read the posting guide http://www.R-project.org/
> > posting-guide.html
> > and provide commented, minimal, self-contained, reproducible code.
> --
>
[[alternative HTML version deleted]]
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