Won't scale(x,center=F, scale=x[1,]) do the trick?
--
Abhijit
Quoting Gabor Grothendieck <[EMAIL PROTECTED]>:
> This should work whether your data, x, is a data frame or a matrix:
>
> x / x[rep(1, nrow(x)),]
>
>
> On Thu, Jul 3, 2008 at 6:04 PM, Greg Kettler <[EMAIL PROTECTED]>
wrote:
>> Hi,
>> I'd like to normalize a dataset by dividing each row by the first
row.
>> Very simple, right?
>> I tried this:
>>
>>> expt.fluor
>> X1 X2 X3
>> 1 124 120 134
>> 2 165 163 174
>> 3 52 51 43
>> 4 179 171 166
>> 5 239 238 235
>>
>>> first.row <- expt.fluor[1,]
>>> normed <- apply(expt.fluor, 1, function(r) {r / first.row})
>>> normed
>> [[1]]
>> X1 X2 X3
>> 1 1 1 1
>>
>> [[2]]
>> X1 X2 X3
>> 1 1.330645 1.358333 1.298507
>>
>> [[3]]
>> X1 X2 X3
>> 1 0.4193548 0.425 0.3208955
>>
>> [[4]]
>> X1 X2 X3
>> 1 1.443548 1.425 1.238806
>>
>> [[5]]
>> X1 X2 X3
>> 1 1.927419 1.983333 1.753731
>>
>> Ugly! The values are right, but why didn't I get another 2D array
>> back? Shouldn't the division in my inline function return a
vector?
>>
>> Thanks,
>> Greg
>>
>> ______________________________________________
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>>
>
> ______________________________________________
> R-help@r-project.org mailing list
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>
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