Hi Bayan,
In your code, 'a' is a vector and is.integer(a) is a logical of length 1 -
most likely FALSE if even one element of a is not an integer. (Since R will
coerce all the elements of a to the same type.)
You need to decide whether something "close enough" to an integer is to be
considered an integer - e.g. a distance of 0.000001 = 1e-6.
a <- df$age
df <- df[ c( TRUE, abs( a - round(a,0) )%%1 ) > 1e-6 ), ]
I added the 'TRUE' at the beginning to always keep the first row of df. If
you prefer to always keep the last row then move the TRUE to the end.
HTH,
Eric
On Tue, Sep 26, 2017 at 12:50 PM, bayan sardini <sardiniba...@gmail.com>
wrote:
> Hi
>
> I want to clean my data frame, based on the age column, whereas i want to
> delete the rows that the difference between its elements (i+1)-i= integer.
> i used
>
> a <- diff(df$age)
> for(i in a){if(is.integer(a) == true){df <- df[-a,]
> }}
>
> but, it doesn’t work, any ideas
>
> Thanks in advance
> Bayan
> ______________________________________________
> R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide http://www.R-project.org/
> posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
[[alternative HTML version deleted]]
______________________________________________
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
