... Or if you just want to stick with basic regex's without extra packages:
> x <- "\"cm_ffm\":\"563.77\"" > sub("[^[:digit:]]*([[:digit:]]*.?[[:digit:]]*).*","\\1",x) [1] "563.77" Cheers, Bert On Wed, Aug 2, 2017 at 5:16 PM, Ismail SEZEN <sezenism...@gmail.com> wrote: > >> On 3 Aug 2017, at 02:59, Christofer Bogaso <bogaso.christo...@gmail.com> >> wrote: >> >> Hi again, >> >> I am struggling to extract the number part from below string : >> >> "\"cm_ffm\":\"563.77\"" >> >> Basically, I need to extract 563.77 from above. The underlying number >> can be a whole number, and there could be comma separator as well. >> >> So far I tried below : >> >>> library(stringr) >> >>> str_extract("\"cm_ffm\":\"563.77\"", "[[:digit:]]+") >> >> [1] "563" >> >>> >> >> However, above code is only extracting the integer part. >> >> Could you please help how to achieve that. Thanks, > > > library(readr) > parse_number('"cm_ffm":"563.77”') > > ______________________________________________ > R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. ______________________________________________ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.