Hi,
On 07/23/2017 11:43 AM, Davide Piffer wrote:
I have a df with a vector v. For each element of the vector, I want to
know whether the i-2nd element is the same as the ith element. For
example:
given
v=c(A,C,D,C) the result should be:
FALSE,FALSE,FALSE,TRUE.
I attempted something using indexing in a for loop such as (bad,
incorrect example):
for (i in v){
if [i]==[i-2] print T
else print F
}
However, this is obviously wrong.
Why don't you provide code that is actually valid R code so we
can run it. Then we can see if it does the right thing or not.
Can someone provide a nice way to solve this?
Does this do what you want?
isSameAsPrevious <- function(v, k=1) c(rep(FALSE, k), head(v,n=-k) ==
tail(v, n=-k))
Then:
> isSameAsPrevious(v, 2)
[1] FALSE FALSE FALSE TRUE
H.
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--
Hervé Pagès
Program in Computational Biology
Division of Public Health Sciences
Fred Hutchinson Cancer Research Center
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P.O. Box 19024
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
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