> On Jun 13, 2017, at 4:10 PM, Rolf Turner <r.tur...@auckland.ac.nz> wrote:
>
> On 14/06/17 08:46, matthias worni wrote:
>> Hey
>> This should be a rather simple quesiton for some of you. I want to make
>> some progress in looping...
>> I have the vector r, which contains single values --> see below:
>> r
>> [1] 1.1717118 1.1605215 1.1522907 1.1422830 1.1065277 1.1165451 1.1163768
>> 1.1048872 1.0848836 1.0627211
>> [11] 1.0300964 1.0296879 1.0308194 1.0518188 1.0657229 1.0685514 1.0914881
>> 1.1042577 1.1039351 1.0880163
>> I would like to take out simply the value "0.990956" from the vector,
>> printing out the rest of it. The code is from the internet but does not
>> seem to work for my vector.
I'm not sure that the source of this code should be considered a trusted
foundation for learning R. You should not be using for-loops to modify vectors
in this manner.
>> Can't figure out why... Thanks for the help
>> r <- as.vector(lw)
That's probably not needed.
>> count=0
>> for (i in r) {
>> if(i == 0.990956) {
>> break
I suspect you meant to use:
?'next' # since `break` completely terminates a for-loop.
The ?'help' page has all the "control structures": `for`, `repeat`, `while` and
associated boundaries and terminators
Both `break` and `next` are reserved words (names of functions, control
tokens), so using the `?` operator requires quoting.
Also that for-next loop would do _nothing_ to the value of r. Printing would
not modify the value of `r`.
You should read:
?Reserved
?'for' # since `for` is also reserved
?print
>> }
>> print(i)
>> }
>
> FAQ 7.31
After following Rolf's advice ... Try:
r[ all.equal(r, 0.990956) ]
>
> cheers,
>
> Rolf Turner
Further note to matthias:
All caps in Subject is considered poor form, as is posting in HTML.
--
David Winsemius
Alameda, CA, USA
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