Hi seems to me like homework, this list has no homework policy.
For linear decay you can use > temp<-c(10,9,8,7,6,5,4,3,2,1) > plus <- seq(10,5, length=10)/100 > plot(1:10, temp, ylim=c(0, max(temp+plus))) > lines(1:10, temp+temp*plus) > lines(1:10, temp-temp*plus) > for exponential you should solve equation plus=a*exp(k*t) for 10 = 0.1 and 1 = 0.05. Cheers Petr > -----Original Message----- > From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of Pedro > páramo > Sent: Friday, June 2, 2017 8:37 AM > To: Bert Gunter <bgunter.4...@gmail.com> > Cc: R-help <r-help@r-project.org> > Subject: Re: [R] Upper bands and lower bands > > Sorry, > > For me a vector is a matrix with mx1 dimmensions. But it is true that it is > not > the way I correctly must talk in R. > > Can you guide me in what I´m trying to do? I´m trying to find what I want in > Excel using something like a parabolic function but dind´t get yet (then to > try > to replicate in R). > > > 2017-06-02 7:01 GMT+02:00 Bert Gunter <bgunter.4...@gmail.com>: > > > Bert Gunter > > > > "The trouble with having an open mind is that people keep coming along > > and sticking things into it." > > -- Opus (aka Berkeley Breathed in his "Bloom County" comic strip ) > > > > > > On Thu, Jun 1, 2017 at 11:20 AM, Pedro páramo <percentil...@gmail.com> > > wrote: > > > Hi all > > > > > > I want to add a band of fluctuación (exponential decreading) to a > > > linear deacrecing values > > > > > > Imagine: I have a matrix like c(10,9,8,7,6,5,4,3,2,1) > > > > Ummm... That is not a matrix. It's a vector. > > > > -- Bert > > > > > > > > > > The thing is I want two new lines so that the máximum value of the > > > new colum on the máximum is from 10% to 5% higher and the same > lower > > > for the mínimum > > > > > > the final two matix will be something like > > > > > > c(10+0.10*10,9+0.089*9,8+0.075*8.....,1+0.05*1) > > > c(10-0.10*10,9-0.09*9,8-0.075*8.....,1-0.05*1) > > > > > > What I´m looking for is a function tu calculate de "values, weights" > > > so that including the 10% and 5% and the nunmber of decreasing > > > values, in > > this > > > case n=10, calculates de smotth weigths. > > > > > > I don´t know if I have expalined well so thar finally putting > > > initial > > value > > > final and periods I can find a matrix like > > > > > > g(0.1,0.89,0.79,0.075,...,0.05) > > > > > > Exists something like that? > > > > > > [[alternative HTML version deleted]] > > > > > > ______________________________________________ > > > R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see > > > https://stat.ethz.ch/mailman/listinfo/r-help > > > PLEASE do read the posting guide http://www.R-project.org/ > > posting-guide.html > > > and provide commented, minimal, self-contained, reproducible code. > > > > [[alternative HTML version deleted]] > > ______________________________________________ > R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting- > guide.html > and provide commented, minimal, self-contained, reproducible code. ________________________________ Tento e-mail a jakékoliv k němu připojené dokumenty jsou důvěrné a jsou určeny pouze jeho adresátům. 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