assign(paste("list_", i, "[[1]]", sep = ""), 5) creates a new variable with a funny name.
You'd have to parse() and eval() to make that work, something like eval(parse(text=paste("list_",i,"[[1]]<-",5, sep=""))) However, ------- > fortunes::fortune("parse") If the answer is parse() you should usually rethink the question. -- Thomas Lumley R-help (February 2005) ------- It is much easier to handle this using a data structure containing a list of lists: l <- rep(list(list()), 10) for ( i in 1:10 ) l[[i]][[1]] <- 5 > On 30 Apr 2017, at 17:17 , Jinsong Zhao <jsz...@yeah.net> wrote: > > Hi there, > > I have a problem with assign(). Here is the demo code: > > for (i in 1:10) { > # create a list with variable name as list_1, list_2, ..., etc. > assign(paste("list_", i, sep = ""), list()) > # I hope to assign 5 to list_?[[1]], but I don't know how to code it. > # list_1[[1]] <- 5 # works, however > assign(paste("list_", i, "[[1]]", sep = "", 5) # does not work > } > > How to do? Is there any alternatives? Many thanks! > > Best, > Jinsong > > ______________________________________________ > R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. -- Peter Dalgaard, Professor, Center for Statistics, Copenhagen Business School Solbjerg Plads 3, 2000 Frederiksberg, Denmark Phone: (+45)38153501 Office: A 4.23 Email: pd....@cbs.dk Priv: pda...@gmail.com ______________________________________________ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.