Hi Alejandro,
How about:
-sign(x) * sign(x) * x
Jim
On Fri, Feb 10, 2017 at 6:30 AM, Alejandro <a.gonzalezvo...@gmail.com> wrote:
> Hello,
>
> I’ve tried googling for an answer to this but I simply can’t find something
> that fixes my problem. I have a long numerical vector with positive, negative
> and null values. I want to revert the sign of the positive and negative
> values and for zero to remain zero. I’ve written a function that works,
> except that my vector has missing values (NA) and I need to keep those as
> missing values. How could I add that to this function:
>
> revertsign<-function(x){
> if (x > 0) {x <- x*-1}
> else
> if (x < 0) {x <- abs(x)}
> else
> if (x == 0) {x <- 0}
> }
>
> I’ve tried if(is.na(x)) {x <- NA} but I get the following error message:
> Error in if (x > 0) { : missing value where TRUE/FALSE needed. Which I guess
> is the first NA in the vector which fails the first if of the function.
>
> I use supply() to run the function on a vector.
>
> Thanks for any assistance.
>
> Cheers
>
> Alejandro
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