Thanks for the reproducible example.
Using regular expressions:
sub(".*HS_(.).*", "\\1", dimInfo[grep("HS_",dimInfo)])
The grep() gets just the indices that contain "HS_" and the sub()
picks up the character you want from the subvector indexed by them and
replaces everything with it.
Cheers,
Bert
Bert Gunter
"The trouble with having an open mind is that people keep coming along
and sticking things into it."
-- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
On Thu, Sep 15, 2016 at 9:17 AM, Doran, Harold <hdo...@air.org> wrote:
> I have produced a terribly inefficient piece of codes. In the end, it gives
> exactly what I need, but clumsily steps through multiple steps which I'm sure
> could be more efficiently reduced.
>
> Below is a reproducible example. What I have to begin with is character
> vector, dimInfo. What I want to do is parse this vector 1) find the elements
> containing 'HS' and 2) grab *only* the first character after the "HS_". The
> final line of code in the example gives what I need.
>
> Any suggestions on a better approach?
>
> Harold
>
>
> dimInfo <- c("RecordID", "oppID", "position", "key", "operational",
> "IsSelected",
> "score", "item_1_HS_conv_ovrl_scr", "item_1_HS_elab_ovrl_scr",
> "item_1_HS_org_ovrl_scr")
>
> ff <- dimInfo[grep('HS', dimInfo)]
> gg <- strsplit(ff, 'HS_')
> hh <- sapply(1:3, function(i) gg[[i]][2])
> substr(hh, 1, 1)
>
> ______________________________________________
> R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
______________________________________________
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
