oh I forgot I renamed sm.
dt = sm
library(data.table)
setDT(dt)
op = function(s){
mean0 = apply(s, 1, mean)
ret = s[which.max(mean0)]
ret$mean = mean0
ret
}
max_row = dt[, op(.SD), by = "Gene"]
Thanks,
Jeremiah
On Thu, Aug 18, 2016 at 3:21 PM, jeremiah rounds <roundsjerem...@gmail.com>
wrote:
> library(data.table)
> setDT(dt)
> op = function(s){
> mean0 = apply(s, 1, mean)
> ret = s[which.max(mean0)]
> ret$mean = mean0
> ret
> }
> max_row = dt[, op(.SD), by = "Gene"]
>
> Thanks,
> Jeremiah
>
> On Thu, Aug 18, 2016 at 2:33 PM, Adrian Johnson <oriolebaltim...@gmail.com
> > wrote:
>
>> Hi Group,
>> I have a data matrix sm (dput code given below).
>>
>> I want to create a data matrix with rows with same variable that have
>> higher mean.
>>
>> > sm
>> Gene GSM529305 GSM529306 GSM529307 GSM529308
>> 1 A1BG 6.57 6.72 6.83 6.69
>> 2 A1CF 2.91 2.80 3.08 3.00
>> 3 A2LD1 5.82 7.01 6.62 6.87
>> 4 A2M 9.21 9.35 9.32 9.19
>> 5 A2M 2.94 2.50 3.16 2.76
>> 6 A4GALT 6.86 5.75 6.06 7.04
>> 7 A4GNT 3.97 3.56 4.22 3.88
>> 8 AAA1 3.39 2.90 3.16 3.23
>> 9 AAAS 8.26 8.63 8.40 8.70
>> 10 AAAS 6.82 7.15 7.33 6.51
>>
>> For example in rows 4 and 5 have same variable Gene A2M. I want to
>> select only row that has higher mean. I wrote the following code that
>> gives me duplicate rows with higher mean but I cannot properly write
>> the result. Could someone help. Thanks
>>
>> ugns <- unique(sm$Gene)
>>
>> exwidh = c()
>>
>> for(i in 1:length(ugns)){
>> k = ugns[i]
>> exwidh[i] <- sm[names(sort(rowMeans(sm[which(sm[,1]==k),2:ncol(sm)]),decr
>> easing=TRUE)[1]),]
>> }
>>
>>
>>
>>
>>
>> structure(list(Gene = c("A1BG", "A1CF", "A2LD1", "A2M", "A2M",
>> "A4GALT", "A4GNT", "AAA1", "AAAS", "AAAS"), GSM529305 = c(6.57,
>> 2.91, 5.82, 9.21, 2.94, 6.86, 3.97, 3.39, 8.26, 6.82), GSM529306 = c(6.72,
>> 2.8, 7.01, 9.35, 2.5, 5.75, 3.56, 2.9, 8.63, 7.15), GSM529307 = c(6.83,
>> 3.08, 6.62, 9.32, 3.16, 6.06, 4.22, 3.16, 8.4, 7.33), GSM529308 = c(6.69,
>> 3, 6.87, 9.19, 2.76, 7.04, 3.88, 3.23, 8.7, 6.51)), .Names = c("Gene",
>> "GSM529305", "GSM529306", "GSM529307", "GSM529308"), row.names = c(NA,
>> 10L), class = "data.frame")
>>
>> ______________________________________________
>> R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
>> https://stat.ethz.ch/mailman/listinfo/r-help
>> PLEASE do read the posting guide http://www.R-project.org/posti
>> ng-guide.html
>> and provide commented, minimal, self-contained, reproducible code.
>>
>
>
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