Not sure it would be any smarter, but what about: a <- c(5.78, 5.79,5.86) n <- 10 matrix(rep(a,each=n), nrow=n)
That way, it would be easy to build a function with 'a' and 'n' as arguments.
HTH, Ivan -- Ivan Calandra, PhD Scientific Mediator University of Reims Champagne-Ardenne GEGENAA - EA 3795 CREA - 2 esplanade Roland Garros 51100 Reims, France +33(0)3 26 77 36 89 ivan.calan...@univ-reims.fr -- https://www.researchgate.net/profile/Ivan_Calandra https://publons.com/author/705639/ Le 01/08/2016 à 11:27, roslinazairimah zakaria a écrit :
Dear r-users, I have a set of numbers that I would like to repeat for let say 10 times and each number is repeated by vertically. I tried this: a <- c(5.78, 5.79,5.86) tran_a <- t(matrix(rep.int(a, 10),3)) dput(tran_a) structure(c(5.78, 5.78, 5.78, 5.78, 5.78, 5.78, 5.78, 5.78, 5.78, 5.78, 5.79, 5.79, 5.79, 5.79, 5.79, 5.79, 5.79, 5.79, 5.79, 5.79, 5.86, 5.86, 5.86, 5.86, 5.86, 5.86, 5.86, 5.86, 5.86, 5.86), .Dim = c(10L, 3L)) Or is there any smarter way? Best regards,
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