A reproducible example makes your problem easier to understand.
ir. Thierry Onkelinx
Instituut voor natuur- en bosonderzoek / Research Institute for Nature and
Forest
team Biometrie & Kwaliteitszorg / team Biometrics & Quality Assurance
Kliniekstraat 25
1070 Anderlecht
Belgium
To call in the statistician after the experiment is done may be no more
than asking him to perform a post-mortem examination: he may be able to say
what the experiment died of. ~ Sir Ronald Aylmer Fisher
The plural of anecdote is not data. ~ Roger Brinner
The combination of some data and an aching desire for an answer does not
ensure that a reasonable answer can be extracted from a given body of data.
~ John Tukey
2016-07-27 15:14 GMT+02:00 sri vathsan <srivib...@gmail.com>:
> Hi,
>
> I created list of 3 combination numbers (mycombos, around 3 lakh
> combinations) and counting the occurrence of those combination in another
> list. This comparision list (mylist) is having around 8000 records.I am
> using the following code.
>
> myCounts <- sapply(1:nrow(myCombos), FUN=function(i) {
> sum(sapply(myList, function(j) {
> sum(!is.na(match(c(myCombos[i,]), j)))})==3)})
>
> The above code takes very long time to execute and is there any other
> effecting method which will reduce the time.
> --
>
> Regards,
> Srivathsan.K
>
> [[alternative HTML version deleted]]
>
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> and provide commented, minimal, self-contained, reproducible code.
>
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