Hi

On top of what Duncan wrote you can check results yourself

> str(iris[,"Sepal.Length"])
num [1:150] 5.1 4.9 4.7 4.6 5 5.4 4.6 5 4.4 4.9 ...

here you get vector and data.frame class is lost. The result is same as
> str(iris$Sepal.Length)
num [1:150] 5.1 4.9 4.7 4.6 5 5.4 4.6 5 4.4 4.9 ...

However

> str(iris["Sepal.Length"])
'data.frame':   150 obs. of  1 variable:
$ Sepal.Length: num  5.1 4.9 4.7 4.6 5 5.4 4.6 5 4.4 4.9 ...

here the data frame class is preserved.

I subscript rectangular objects (arrays, matricex, data, frames) exclusively by

object[ , , something, ] or in case of data frame object.df[sub, ]

and lists with

object.l[sub] or object.l[[sub]]

so I never had problems with it.

Cheers
Petr


From: g.maub...@weinwolf.de [mailto:g.maub...@weinwolf.de]
Sent: Monday, June 27, 2016 1:43 PM
To: PIKAL Petr <petr.pi...@precheza.cz>
Cc: r-help@r-project.org
Subject: Antwort: RE: [R] Antwort: Fw: Re: Subscripting problem with is.na()

Hi Petr,

many thanks for your reply and the examples.

My subscripting problems drive me nuts.

I have understood that dataset[variable] is semantically identical to dataset[, 
variable] cause dataset[variable] takes all cases because no other subscripts 
are given.

Where can I lookup the rules when to use the comma and when not?

Kind regards

Georg





Von:        PIKAL Petr <petr.pi...@precheza.cz<mailto:petr.pi...@precheza.cz>>
An:        "g.maub...@weinwolf.de<mailto:g.maub...@weinwolf.de>" 
<g.maub...@weinwolf.de<mailto:g.maub...@weinwolf.de>>,
Kopie:        "r-help@r-project.org<mailto:r-help@r-project.org>" 
<r-help@r-project.org<mailto:r-help@r-project.org>>
Datum:        27.06.2016 11:03
Betreff:        RE: [R] Antwort: Fw: Re:  Subscripting problem with is.na()
________________________________



Hi

see in line

> -----Original Message-----
> From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of
> g.maub...@weinwolf.de<mailto:g.maub...@weinwolf.de>
> Sent: Monday, June 27, 2016 10:45 AM
> To: David L Carlson <dcarl...@tamu.edu<mailto:dcarl...@tamu.edu>>; Bert Gunter
> <bgunter.4...@gmail.com<mailto:bgunter.4...@gmail.com>>
> Cc: r-help@r-project.org<mailto:r-help@r-project.org>
> Subject: [R] Antwort: Fw: Re: Subscripting problem with is.na()
>
> Hi David,
> Hi Bert,
>
> many thanks for the valuable discussion on NA in R (please see extract
> below). I follow your arguments leaving NA as they are for most of the
> time. In special occasions however I want to replace the NA with another
> value. To preserve the newly acquired knowledge for me I wrote this
> function:
>
> -- cut --
> t_replace_na <- function(dataset, variable, value) {
>  if(inherits(dataset[[variable]], "factor") == TRUE) {
>    dataset[variable] <- as.character(dataset[variable])
>    print(class(dataset[variable]))
>    dataset[, variable][is.na(dataset[, variable])] <- value
>    dataset[variable] <- as.factor(dataset[variable])
>    print(class(dataset[variable]))
>  } else {
>    dataset[, variable][is.na(dataset[, variable])] <- value
>  }
>  return(dataset)
> }
>

<snip>

> class(ds_test[, "c"])
> test_class(ds_test, "c")
> warning("'c' should be factor NOT data.frame.
> In addition data.frame != factor")
> -- cut --
>
> Why do I get different results for the same function if it is inside or
> outside my own function definition?

Because you still are missing the way how to subscript data frames.

test_class <- function(dataset, variable) {
 if(inherits(dataset[, variable], "factor") == TRUE) {
   return(c(class(dataset[,variable]), TRUE))
####                                 ^^^^
} else {
   return(c(class(dataset[,variable]), FALSE))
######                            ^^^^
 }
}

> test_class(ds_test, "a")
[1] "numeric" "FALSE"
> test_class(ds_test, "c")
[1] "factor" "TRUE"
>

If you properly arrange commas in your function you get desired result

p_replace_na <- function(dataset, variable, value) {
if(inherits(dataset[,variable], "factor") == TRUE) {
  dataset[,variable] <- as.character(dataset[,variable])
  print(class(dataset[,variable]))
  dataset[, variable][is.na(dataset[, variable])] <- value
  dataset[, variable] <- as.factor(dataset[, variable])
  print(class(dataset[, variable]))
} else {
  dataset[, variable][is.na(dataset[, variable])] <- value
}
return(dataset)
}

> p_replace_na(ds_test, "c", value = -3)
[1] "character"
[1] "factor"
  a  b  c
1  1 NA  A
2 NA NA  b
3  2 NA -3

> t_replace_na(ds_test, "c", value = -3)
[1] "data.frame"
Error in sort.list(y) : 'x' must be atomic for 'sort.list'
Have you called 'sort' on a list?
>

Cheers
Petr



>
> Kind regards
>
> Georg
>
> --------------------------------
>
> > Gesendet: Donnerstag, 23. Juni 2016 um 21:14 Uhr
> > Von: "David L Carlson" <dcarl...@tamu.edu<mailto:dcarl...@tamu.edu>>
> > An: "Bert Gunter" <bgunter.4...@gmail.com<mailto:bgunter.4...@gmail.com>>
> > Cc: "R Help" <r-help@r-project.org<mailto:r-help@r-project.org>>
> > Betreff: Re: [R] Subscripting problem with is.na()
> >
> > Good point. I did not think about factors. Also your example raises
> another issue since column c is logical, but gets silently converted to
> numeric. This would seem to get the job done assuming the conversion is
> intended for numeric columns only:
> >
> > > test <- data.frame(a=c(1,NA,2), b = c("A","b",NA), c= rep(NA,3))
> > > sapply(test, class)
> >         a         b         c
> > "numeric"  "factor" "logical"
> > > num <- sapply(test, is.numeric)
> > > test[, num][is.na(test[, num])] <- 0
> > > test
> >   a    b  c
> > 1 1    A NA
> > 2 0    b NA
> > 3 2 <NA> NA
> >
> > David C
>
> ______________________________________________
> R-help@r-project.org<mailto:R-help@r-project.org> mailing list -- To 
> UNSUBSCRIBE and more, see
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide 
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