?lower.tri
> tmp <- matrix(scan(text=" NaN 45 63.43495
+ 45.00000 NaN 90.00000
+ 63.43495 90 NaN"), 3, 3)
Read 9 items
> tmp
[,1] [,2] [,3]
[1,] NaN 45 63.43495
[2,] 45.00000 NaN 90.00000
[3,] 63.43495 90 NaN
> lower.tri(tmp)
[,1] [,2] [,3]
[1,] FALSE FALSE FALSE
[2,] TRUE FALSE FALSE
[3,] TRUE TRUE FALSE
> tmp[lower.tri(tmp)]
[1] 45.00000 63.43495 90.00000
On Mon, May 16, 2016 at 12:10 PM, Denis Francisci
<denis.franci...@gmail.com> wrote:
> Hi all,
> I've a simple question.
> I have a matrix with same values over and under the diagonal. That's an
> example:
> [,1] [,2] [,3]
> [1,] NaN 45 63.43495
> [2,] 45.00000 NaN 90.00000
> [3,] 63.43495 90 NaN
> How can I extract just the three values over (or under) the diagonal and
> convert them in a vector like this: 45, 63.43495, 90 ?
>
> Thank's in advance
>
> [[alternative HTML version deleted]]
>
> ______________________________________________
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> and provide commented, minimal, self-contained, reproducible code.
______________________________________________
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
