Hi Georg,
The " around Kunden$* looks unintentional to me.
Second: haveyou considered using a long table? Then you would fill a known
set of columns.
Third if you must have columns based on year I believe df[[a.column.name]]
will work.
Best
Ulrik
<g.maub...@gmx.de> schrieb am Sa., 23. Apr. 2016 07:33:
> Hi all,
>
> I would like to use a loop for tasks that occurs repeatedly:
>
> # Groups
> # Umsatz <= 0: 1 (NICHT kaufend)
> # Umsatz > 0: 2 (kaufend)
> for (year in c("2011", "2012", "2013", "2014", "2015")) {
> paste0("Kunden$Kunde_real_", year) <- (paste0("Kunden$Umsatz_", year) <=
> 0) * 1 +
> (paste0("Kunden$Umsatz_", year) >
> 0) * 2
> paste0("Kunden$Kunde_real_", year) <- factor(paste0("Kunden$Umsatz_",
> year),
> levels = c(1, 2),
> labels = c("NICHT kaufend",
> "kaufend"))
> }
>
> This actually does not work due to the fact that the expression
> "paste0("Kunden$Kunde_real_", year)" ist not interpreted as a variable name
> by the R script language interpreter.
>
> Is there a way to assembly variable names on the fly in R?
>
> Regards
>
> Georg
>
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