... or try to avoid unnecessarily complex code, and just type
sapply(parse(text=xxx), eval)
vQ
Kenn Konstabel wrote:
> another way to do it is using eval and parse:
>
> yyy<-numeric()
> for(i in 1:length(xxx)) yyy[i] <- eval(parse(text=xxx[i]))
>
> or ...
>
> unlist(lapply(as.list(xxx), function(x) eval(parse(text=x))))
>
> then xxx can contain any valid expressions (not necessarily fractions)
>
> Kenn
>
> On Sat, Jun 21, 2008 at 12:44 PM, Hans-Jörg Bibiko <[EMAIL PROTECTED]>
> wrote:
>
>
>> On 21.06.2008, at 01:36, Ken Liu wrote:
>>
>>
>>> I would like to convert a character vector
>>>
>>> xxx <- c("1/2", "1/4")
>>>
>>> to
>>>
>>> yyy <- c(0.5, 0.25)
>>>
>>>
>>> , but as.numeric didn't work for me. Could anyone give me a hint please?
>>>
>>>
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