... and a slightly more efficient non-dplyr 1-liner:
> sapply(strsplit(dd$Lower,"[^[:digit:]]"),
function(x)sum(as.numeric(x), na.rm=TRUE))
[1] 105 67 60 100 80
Cheers,
Bert
Bert Gunter
"The trouble with having an open mind is that people keep coming along
and sticking things into it."
-- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
On Mon, Apr 18, 2016 at 10:43 AM, Bert Gunter <bgunter.4...@gmail.com> wrote:
> ... and here is a non-dplyr rsolution:
>
>> z <-gsub("[^[:digit:]]"," ",dd$Lower)
>
>> sapply(strsplit(z," +"),function(x)sum(as.numeric(x),na.rm=TRUE))
> [1] 105 67 60 100 80
>
>
> Cheers,
> Bert
> Bert Gunter
>
> "The trouble with having an open mind is that people keep coming along
> and sticking things into it."
> -- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
>
>
> On Mon, Apr 18, 2016 at 10:07 AM, Richard M. Heiberger <r...@temple.edu>
> wrote:
>> ## Continuing with your data
>>
>> AA <- stringr::str_extract_all(dd[[2]],"[[:digit:]]+")
>> BB <- lapply(AA, as.numeric)
>> ## I think you are looking for one of the following two expressions
>> sum(unlist(BB))
>> sapply(BB, sum)
>>
>>
>> On Mon, Apr 18, 2016 at 12:48 PM, Burhan ul haq <ulh...@gmail.com> wrote:
>>> Hi,
>>>
>>> I request help with the following:
>>>
>>> INPUT: A data frame where column "Lower" is a character containing numeric
>>> values (different count or occurrences of numeric values in each row,
>>> mostly 2)
>>>
>>>> dput(dd)
>>> structure(list(State = c("Alabama", "Alaska", "Arizona", "Arkansas",
>>> "California"), Lower = c("R 72–33", "R/Coalition 27(23 R, 4 D)–12 D, 1
>>> Ind.",
>>> "R 36–24", "R 64–35, 1 Ind.", "D 52–28"), Upper = c("R 26–8, 1 Ind.",
>>> "R/Coalition 15(14 R, 1 D)–5 D", "R 18–12", "R 24–11", "D 26–14"
>>> )), .Names = c("State", "Lower", "Upper"), row.names = c(NA,
>>> 5L), class = "data.frame")
>>>
>>> PROBLEM: Need to extract all numeric values and sum them. There are few
>>> exceptions like row2. But these can be ignored and will be fixed manually
>>>
>>> SOLUTION SO FAR:
>>> str_extract_all(dd[[2]],"[[:digit:]]+"), returns a list of numbers as
>>> character. I am unable to unlist it, because it mixes them all together, ...
>>>
>>> And if I may add, is there a "dplyr" way of doing it ...
>>>
>>>
>>> Thanks
>>>
>>> [[alternative HTML version deleted]]
>>>
>>> ______________________________________________
>>> R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
>>> https://stat.ethz.ch/mailman/listinfo/r-help
>>> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
>>> and provide commented, minimal, self-contained, reproducible code.
>>
>> ______________________________________________
>> R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
>> https://stat.ethz.ch/mailman/listinfo/r-help
>> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
>> and provide commented, minimal, self-contained, reproducible code.
______________________________________________
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
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