Fyi, This statement returned the following error
'Error in "Yes" + 0 : non-numeric argument to binary operator'
On Thu, Apr 7, 2016 at 8:43 AM, <ruipbarra...@sapo.pt> wrote:
> Hello,
>
> Or even simpler, without ifelse,
>
> colordata$response <- colordata$color == 'blue' + 0
>
> Hope this helps,
>
> Rui Barradas
>
>
> Citando David Barron <dnbar...@gmail.com>:
>
> ifelse is vectorised, so just use that without the loop.
>
> colordata$response <- ifelse(colordata$color == 'blue', 1, 0)
>
> David
>
> On 7 April 2016 at 12:41, Michael Artz <michaelea...@gmail.com> wrote:
>
> Hi I'm not sure how to ask this, but its a very easy question to answer for
> an R person.
>
> What is an easy way to check for a column value and then assigne a new
> column a value based on that old column value?
>
> For example, Im doing
> colordata <- data.frame(id = c(1,2,3,4,5), color = c("blue", "red",
> "green", "blue", "orange"))
> for (i in 1:nrow(colordata)){
> colordata$response[i] <- ifelse(colordata[i,"color"] == "blue", 1, 0)
> }
>
> which works, but I don't want to use the for loop I want to "vecotrize"
> this. How would this be implemented?
>
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>
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>
> ______________________________________________
> R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
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> PLEASE do read the posting guide
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> minimal, self-contained, reproducible code.
>
>
>
>
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