On 03/03/2016 02:13 PM, KMNanus wrote:
When I do that,
When you do what exactly?
It's impossible for anyone here to know what you're doing if you
don't show the code.
I get "Error in `$<-.data.frame`(`*tmp*`, "site", value
= integer(0)) :
replacement has 0 rows, data has 6”
The data frame has 6 rows.
You said you had a factor variable, you never mentioned you had a
data.frame. If the factor variable is part of a data.frame 'df',
then first extract it with something like df$myvar or df[["myvar"]],
and then call substr() followed by as.factor() on it.
H.
Ken
kmna...@gmail.com <mailto:kmna...@gmail.com>
914-450-0816 (tel)
347-730-4813 (fax)
On Mar 3, 2016, at 4:52 PM, Hervé Pagès <hpa...@fredhutch.org
<mailto:hpa...@fredhutch.org>> wrote:
Hi,
On 03/03/2016 12:18 PM, KMNanus wrote:
I have a factor variable that is 6 digits and hyphenated. For
example, 001-014.
I need to extract the first 3 digits to a new variable using mutate
in dplyr - in this case 001 - but can’t find a function to do it.
substr will do this for character strings, but I need the variable to
remain as a factor.
What prevents you from calling as.factor() on the result to turn it
back into a factor?
H.
Is there an R function or workaround to do this?
Ken
kmna...@gmail.com <mailto:kmna...@gmail.com>
914-450-0816 (tel)
347-730-4813 (fax)
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--
Hervé Pagès
Program in Computational Biology
Division of Public Health Sciences
Fred Hutchinson Cancer Research Center
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--
Hervé Pagès
Program in Computational Biology
Division of Public Health Sciences
Fred Hutchinson Cancer Research Center
1100 Fairview Ave. N, M1-B514
P.O. Box 19024
Seattle, WA 98109-1024
E-mail: hpa...@fredhutch.org
Phone: (206) 667-5791
Fax: (206) 667-1319
______________________________________________
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.