Thank you for your answer. Please let me provide additional information: You have a pooled variance covariance matrix S (2x2). The matrix needs to be inverted: S^-1.
The calculation of the coeffcients is done by S^-1 (average (x1) - average (x2)). average (x1) is the vector of means (2x1) in group 1, average (x2) is the vector of means (2x1) in group 2. S is as follows [1,1]: 2267168.12; [1,2]: 49088.07 [2,2]: 8381.77 average (x1) is as follows [1,1]: 3510.4; [2,1]: 390.2 average (x2) is as follows [1,1]: 7975.2; [2,1]: 577.5 Means that having the above mentioned formula in mind it is very easy to calculate. However, my problem is, that I am not able to find any way to get this result by using R. Or in another way: What estimates R and is there any possibility to link the both results? Thanks. Gesendet: Donnerstag, 03. März 2016 um 15:08 Uhr Von: "David L Carlson" <dcarl...@tamu.edu> An: "Jens Koch" <jens.k...@gmx.li>, "r-help@r-project.org" <r-help@r-project.org> Betreff: RE: [R] discriminant analysis lda under MASS If the textbook provides the equations, you can work through them directly. But without knowing more, it is hard to say. You could also contact the author of the textbook. ------------------------------------- David L Carlson Department of Anthropology Texas A&M University College Station, TX 77840-4352 -----Original Message----- From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of Jens Koch Sent: Wednesday, March 2, 2016 9:19 AM To: r-help@r-project.org Subject: [R] discriminant analysis lda under MASS Hello all, I'd like to run a simple discriminant analysis to jump into the topic with the following dataset provided by a textbook: Gruppe Einwohner Kosten 1 1642 478,2 1 2418 247,3 1 1417 223,6 1 2761 505,6 1 3991 399,3 1 2500 276 1 6261 542,5 1 3260 308,9 1 2516 453,6 1 4451 430,2 1 3504 413,8 1 5431 379,7 1 3523 400,5 1 5471 404,1 2 7172 499,4 2 9419 674,9 2 8780 468,6 2 5070 601,5 2 5780 578,8 2 8630 641,5 The coefficients according to the textbook need to be -0.00170 and -0.01237. If I put the data into the lda function under MASS, my result is: Call: lda(Gruppe ~ Einwohner + Kosten, data = data) Prior probabilities of groups: 1 2 0.7 0.3 Group means: Einwohner Kosten 1 3510.429 390.2357 2 7475.167 577.4500 Coefficients of linear discriminants: LD1 Einwohner 0.0004751092 Kosten 0.0050994964 I also tried to solve it by an another software package, but there is also not the result I have expected. I know now, that the solution for the coefficients is standardized by R and the discrimination power is not different at the end of the day. But: How can I get (calculate) the results printed in the textbook with R? Thanks in advance, Jens. ______________________________________________ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html[http://www.R-project.org/posting-guide.html] and provide commented, minimal, self-contained, reproducible code. ______________________________________________ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
