Why don't you simply use names(c) to get the names of all objects? If, for your purposes, you still want the "names" function inside lapply, you can use the following: unlist(lapply(1:length(c), function(x) names(c[x]))) This will produce exactly same output as names(c) would. When you use lapply(c, names) then it basically does this: names(c[[1]]) for first member of the list, and that results to NULL. However, names(c[1]) gives you "a".
Hope that helps. On Thu, Feb 25, 2016 at 3:27 PM, Mohammad Tanvir Ahamed via R-help < r-help@r-project.org> wrote: > Hello, > > I want to get object name of a list inside lapply > > > c<-list(a=seq(1:5),b=seq(10:20)) > > lapply(c,names) > $a > NULL > > $b > NULL > > Why NULL ? > > but i am expecting the names of object . Any help will be appreciated . > > I want to grab the names of object inside lapply for further process. > > Thanks . > > > Tanvir Ahamed > Göteborg, Sweden | mashra...@yahoo.com > > ______________________________________________ > R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
