Hi
You shall send your posts to the list, others can answer your questions and not
only you can benefit from their answers too.
As you did not post any data it is hard to say what are your issues. I believe
that there are several values which are the same not only near the peak but
also at the bottom part. If your data look like I remember and you want to keep
all values near the peak value regardless they are slightly growing or falling,
one approach can be to identify peak value, and select all values near the peak
(the threshold is up to you).
something like that
sss<-smooth.spline(temp$theta, temp$int, nknots=length(temp$int)/2)
peak <- which.max(predict(sss)$y)
baseline <- min(predict(sss)$y)
vyska <- predict(sss)$y[peak]
# 50% threshold
HM <- (vyska+baseline)/2
plot(temp$theta, temp$int, col=(temp$int>HM)+1, pch=19)
#10% threshold
HM<-vyska-(vyska*.1)
plot(temp$theta, temp$int, col=(temp$int>HM)+1, pch=19)
> dput(temp)
structure(list(theta = c(28.995, 29.005, 29.015, 29.025, 29.035,
29.045, 29.055, 29.065, 29.075, 29.085, 29.095, 29.105, 29.115,
29.125, 29.135, 29.145, 29.155, 29.165, 29.175, 29.185, 29.195,
29.205, 29.215, 29.225, 29.235, 29.245, 29.255, 29.265, 29.275,
29.285, 29.295, 29.305, 29.315, 29.325, 29.335, 29.345, 29.355,
29.365, 29.375, 29.385, 29.395, 29.405, 29.415, 29.425, 29.435,
29.445, 29.455, 29.465, 29.475, 29.485, 29.495, 29.505, 29.515,
29.525, 29.535, 29.545, 29.555, 29.565, 29.575, 29.585, 29.595,
29.605, 29.615, 29.625, 29.635, 29.645, 29.655, 29.665, 29.675,
29.685, 29.695, 29.705, 29.715, 29.725, 29.735, 29.745, 29.755,
29.765, 29.775, 29.785, 29.795, 29.805, 29.815, 29.825, 29.835,
29.845, 29.855, 29.865, 29.875, 29.885, 29.895, 29.905, 29.915,
29.925, 29.935, 29.945, 29.955, 29.965, 29.975, 29.985, 29.995
), int = c(329L, 330L, 318L, 287L, 315L, 344L, 333L, 324L, 334L,
366L, 339L, 374L, 375L, 335L, 415L, 371L, 413L, 382L, 408L, 406L,
407L, 440L, 475L, 465L, 516L, 510L, 490L, 550L, 663L, 647L, 628L,
721L, 789L, 814L, 890L, 923L, 1085L, 1102L, 1222L, 1356L, 1521L,
1729L, 1868L, 2120L, 2491L, 2656L, 3196L, 3599L, 4128L, 4536L,
5043L, 5310L, 5638L, 5792L, 5699L, 5374L, 4886L, 4473L, 4293L,
3757L, 3319L, 2934L, 2422L, 1998L, 1753L, 1397L, 1163L, 972L,
854L, 775L, 648L, 695L, 616L, 553L, 554L, 509L, 530L, 483L, 482L,
406L, 451L, 422L, 403L, 393L, 396L, 348L, 367L, 428L, 345L, 384L,
330L, 342L, 312L, 313L, 323L, 328L, 340L, 322L, 330L, 305L, 311L
)), .Names = c("theta", "int"), row.names = 100:200, class = "data.frame")
>
Cheers
Petr
From: Makram Belhaj Fraj [mailto:belhajfraj.mak...@gmail.com]
Sent: Tuesday, December 29, 2015 5:54 AM
To: PIKAL Petr
Subject: Re: [R] need for help for solving operations in a vector
Hi Petr,
I would like to thank you for your time
i choose the following modification on the plotting so to keep only successive
equals in red
plot(qWC1, col=(c(0, diff(qWC1))==0 )+1)
then, the red points I want to include in the irrigation period are the 3
successive red points in the plateau (equal values close to the max)
These points are very important as they are corresponding to saturation, we
continue to irrigate with the same flow and values remains constant for a
certain time, so I must add them to irrigation
up to now I didn't succeed in adding this plateau values to theirrigations
using the diff(qWC1, lag=1)
however, I wrote also some loops trying to catch all the irrigation and
recharge separately and I still have some issues,
following are the loops I used, with comments corresponding to the issues
x<-qWC1
length(x)
irrig<-rep(1,61)
for (i in 2:61) {
if (x[i-1]<x[i]){
irrig[i]<-x[i]-x[i-1]
}
}
rech<-rep(1,61)
for (i in 2:61) {
if (x[i-1]>x[i]){
rech[i]<-x[i-1]-x[i]
}
}
plot(x, type = "l", col = "black", ylim = c(min(0), max(92)))
lines(irrig, type = "l", col = "cornflowerblue", ylim = c(min(0), max(15)))
lines(rech, type = "l", col = "brown", ylim = c(min(0), max(15)))
temp<-irrig<1.000001 #logical command to identify low values into a temporary
vector temp
temp2<-as.numeric(irrig>1.000001) #logical command to identify high values with
1
temp2
temp3<-as.numeric(rech>1.000001)
temp3
irrig2<-irrig*temp2 #remove values inf 1 mm inirrig
rech2<-rech*temp3 #same for rech
plot(irrig2, type = "l", col = "cornflowerblue", ylim = c(min(0), max(15)))
lines(rech2, type = "l", col = "brown", ylim = c(min(0), max(15)))
Many thanks for your time and intellectual generosity
Cheers
Makram
On Mon, Dec 28, 2015 at 12:15 PM, PIKAL Petr
<petr.pi...@precheza.cz<mailto:petr.pi...@precheza.cz>> wrote:
Hi
On top of answers you have got here is some plotting you need to answer yourself
plot(qWC1, col=(c(0, diff(qWC1))>=0 )+1)
Which from those red points you want to be included in irrigation period? All
of them? Only part? Which part?
Based on your figures you probably will not get 100% correct answer.
Cheers
Petr
> -----Original Message-----
> From: R-help
> [mailto:r-help-boun...@r-project.org<mailto:r-help-boun...@r-project.org>] On
> Behalf Of Makram
> Belhaj Fraj
> Sent: Wednesday, December 23, 2015 8:35 AM
> To: r-help@r-project.org<mailto:r-help@r-project.org>;
> r-help-ow...@r-project.org<mailto:r-help-ow...@r-project.org>
> Subject: [R] need for help for solving operations in a vector
>
> Dear colleagues
> i need your generous help to solve the following problem
>
> I have a soil moisture time series qWC1 (61 values)
> > qWC1
> 75.33336 75.20617 75.20617 74.95275 74.95275 74.70059 74.70059
> 74.70059
> 74.57498 74.44968 74.32469 74.07563 85.57237 90.40123 90.73760
> 90.73760 90.73760 90.73760 90.90648 91.07582 91.24564 90.90648 86.82135
> 80.69793
> 79.30393 78.62058 78.21484 77.81226 77.67876 77.41279 77.28032 76.88495
> 76.75383 76.75383 76.49260 76.36249 76.23270 76.23270 76.10325
> 75.97412
> 75.84532 75.71685 75.71685 75.71685 75.71685 75.46087 75.46087
> 75.46087
> 75.33336 75.20617 75.20617 75.20617 75.20617 75.20617 75.20617 75.07930
> 75.07930 75.07930 74.95275 74.95275 74.95275
>
> I want to measure consecutive increases corresponding to irrigation and
> consecutive decreases corresponding to recharge I wrote the following
> code and it does not calculate for each increment in i?
> also note that I choose to not use diff command in time series because
> I want also that "plateaux" corresponding to a minimum of 2 equal
> consecutive values are accounted as positive differences=irrigations so
> when x[i+1]==x[i] the difference y might be equal to the previous value
> xi
>
> following the code i wrote
>
> x<-ts(qWC1,start=1, end=61, frequency=1) x[1] plot(x, type="h", col =
> "green")
> y<-rep(0,61)
> for (i in 1:61) {
> if (x[i+1] > x[i]){
> y[i]==x[i+1]-x[i]
> } else if (x[i+1]==x[i]){
> y[i]=x[i+2]-x[i]
> } else {
> y[i]==x[i+1]-x[i]
> }
>
> }
> plot(y, type="h", col = "blueviolet")
>
> Many thank
> Makram
>
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