You want to use qf which gives you the value at a given percentile. pf gives you the p-value for a given value of F (inverse)
> qf(0.95, 1, 1) [1] 161.4476 > pf(161.4476, 1, 1) [1] 0.95 Peter On Mon, Dec 21, 2015 at 11:51 AM, Robert Sherry <rsher...@comcast.net> wrote: > > When I use a table, from a Schaum book, I see that for the 95 percentile, > with v_1 = 1 and v_2 = 1 the value is 161. In the modern era, > looking values up in a table is less than ideal. Therefore, I would expect R > to have a function to do this and based upon my > reading of the documentation, I would expect the following call to get the > value I expect: > pf( .95,1, 1) > However, it produces > 0.4918373 > Therefore, I conclude that I am using the wrong function. What function > should I use? > > Thanks > Bob > > ______________________________________________ > R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. ______________________________________________ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
