Dear group, kindly, I have a data frame, as follows:
Measure_id i j value rank 1 1 2 3 2.0 1.0000000 2 1 5 1 2.0 1.0000000 3 1 2 1 1.5 0.7500000 4 1 5 2 1.5 0.7500000 5 1 7 3 1.5 1.0000000 6 1 2 4 1.0 0.5000000 7 1 7 5 1.0 0.6666667 8 2 5 2 2.5 1.0000000 9 2 2 1 2.0 1.0000000 10 2 2 4 2.0 1.0000000 .. ... . . ... ... I want to select distinct rows based on two coulmn ( Measure_id and i ) for example for Measure_id = 1,2 the result would be.... 1 1 2 3 2.0 1.0000000 2 1 5 1 2.0 1.0000000 5 1 7 3 1.5 1.0000000 8 2 5 2 2.5 1.0000000 9 2 2 1 2.0 1.0000000 kindly how I could do this? example of the data frame are followed using dput. dput(orderlist) structure(list(Measure_id = c(1, 1, 1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 2, 3, 3, 3, 3, 3, 3, 3, 4, 4, 4, 4, 4, 4, 4, 5, 5, 5, 5, 5, 5, 5), i = c(2, 5, 2, 5, 7, 2, 7, 5, 2, 2, 7, 2, 5, 7, 2, 2, 2, 5, 5, 7, 7, 2, 5, 2, 2, 5, 7, 7, 2, 2, 5, 2, 5, 7, 7), j = c(3, 1, 1, 2, 3, 4, 5, 2, 1, 4, 5, 3, 1, 3, 1, 3, 4, 1, 2, 3, 5, 4, 2, 1, 3, 1, 3, 5, 1, 4, 2, 3, 1, 3, 5), value = c(2, 2, 1.5, 1.5, 1.5, 1, 1, 2.5, 2, 2, 2, 1.5, 1.5, 1, 1, 0, 0, 0, 0, 0, 0, 1, 1, 0, 0, 0, 0, 0, 2, 2, 2, 1, 1, 1, 1), rank = c(1, 1, 0.75, 0.75, 1, 0.5, 0.666666666666667, 1, 1, 1, 1, 0.75, 0.6, 0.5, 1, 0, 0, NaN, NaN, NaN, NaN, 1, 1, 0, 0, 0, NaN, NaN, 1, 1, 1, 0.5, 0.5, 1, 1)), class = c("grouped_df", "tbl_df", "tbl", "data.frame"), row.names = c(NA, -35L), .Names = c("Measure_id", "i", "j", "value", "rank"), vars = list(Measure_id), indices = list( 0:6, 7:13, 14:20, 21:27, 28:34), group_sizes = c(7L, 7L, 7L, 7L, 7L), biggest_group_size = 7L, labels = structure(list( Measure_id = c(1, 2, 3, 4, 5)), class = "data.frame", row.names = c(NA, -5L), .Names = "Measure_id", vars = list(Measure_id))) thanks in advance Ragia ______________________________________________ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.