The breaks are just the min() and max() in your groups. Something like
sprintf("[%5.2f,%5.2f]", min(dBin[groups==2]), max(dBin[groups==2]))
... should achieve what you need.
B.
On Nov 4, 2015, at 8:45 AM, Alaios <ala...@yahoo.com> wrote:
> you are right.
> by labels I mean the "categories", "breaks" that my data fall in.
> To be part of group 2 for example you have to be in the range of [110,223) I
> need to keep those for my plots.
>
> Did I describe it more precisely now?
> Alex
>
>
>
> On Wednesday, November 4, 2015 2:09 PM, Boris Steipe
> <boris.ste...@utoronto.ca> wrote:
>
>
> I don't understand:
> - where does the "label" come from? (It's not an element of your data that I
> see.)
> - what do you want to do with this "label" i.e. how does it need to be
> associated with the data?
>
>
> B.
>
>
>
> On Nov 4, 2015, at 7:57 AM, Alaios <ala...@yahoo.com> wrote:
>
> > Thanks it works great and gives me group numbers as integers and thus I can
> > with which group the elements as needed (which (groups== 2))
> >
> > Question though is how to keep also the labels for each group. For example
> > that my first group is the [13,206)
> >
> > Regards
> > Alex
> >
> >
> >
> > On Wednesday, November 4, 2015 1:00 PM, Boris Steipe
> > <boris.ste...@utoronto.ca> wrote:
> >
> >
> > I would transform the original numbers into integers which you can use as
> > group labels. The row numbers of the group labels are the indexes of your
> > values.
> >
> > Example: assume your input vector is dBin
> >
> > nGroups <- 5 # number of groups
> > groups <- (dBin - min(dBin)) / (max(dBin) - min(dBin)) # rescale to the
> > range [0,1]
> > groups <- floor(groups * nGroups) + 1 # discretize to nGroups integers
> >
> > Now you can eg. get the indices for group 2
> >
> > groups[groups == 2]
> >
> > Depending on the nature of your input data, it may be better to keep these
> > groups in a column adjacent to your values, rather than in a separate
> > vector, or even better to just calculate the groups on the fly in your
> > downstream analysis with the approach given above in a function, rather
> > than storing them at all. These are simple operations that should not add
> > perceptibly to execution time.
> >
> > Cheers,
> > Boris
> >
> >
> >
> >
> >
> >
> > On Nov 4, 2015, at 6:40 AM, Alaios via R-help <r-help@r-project.org> wrote:
> >
> > > Thanks for the answer. Split does not give me the indexes though but only
> > > in which group they fall in. I also need the index of the group. Is the
> > > first, the second .. group?Alex
> > >
> > >
> > >
> > > On Tuesday, November 3, 2015 5:05 PM, Ista Zahn <istaz...@gmail.com>
> > > wrote:
> > >
> > >
> > > Probably
> > >
> > > split(binDistance, test).
> > >
> > > Best,
> > > Ista
> > >
> > > On Tue, Nov 3, 2015 at 10:47 AM, Alaios via R-help <r-help@r-project.org>
> > > wrote:
> > >> Dear all,I am not exactly sure on what is the proper name of what I am
> > >> trying to do.
> > >> I have a vector that looks like
> > >> binDistance
> > >> [,1]
> > >> [1,] 238.95162
> > >> [2,] 143.08590
> > >> [3,] 88.50923
> > >> [4,] 177.67884
> > >> [5,] 277.54116
> > >> [6,] 342.94689
> > >> [7,] 241.60905
> > >> [8,] 177.81969
> > >> [9,] 211.25559
> > >> [10,] 279.72702
> > >> [11,] 381.95738
> > >> [12,] 483.76363
> > >> [13,] 480.98841
> > >> [14,] 369.75241
> > >> [15,] 267.73650
> > >> [16,] 138.55959
> > >> [17,] 137.93181
> > >> [18,] 184.75200
> > >> [19,] 254.64359
> > >> [20,] 328.87785
> > >> [21,] 273.15577
> > >> [22,] 252.52830
> > >> [23,] 252.52830
> > >> [24,] 252.52830
> > >> [25,] 262.20084
> > >> [26,] 314.93064
> > >> [27,] 366.02996
> > >> [28,] 442.77467
> > >> [29,] 521.20323
> > >> [30,] 465.33071
> > >> [31,] 366.60582
> > >> [32,] 13.69540
> > >> so numbers that start from 13 and go up to maximum 522 (I have also many
> > >> other similar sets).I want to put these numbers into 5 categories and
> > >> thus I have tried cut
> > >>
> > >>
> > >> Browse[2]>
> > >> test<-cut(binDistance,seq(min(binDistance)-0.00001,max(binDistance),length.out=scaleLength+1))
> > >> Browse[2]> test
> > >> [1] (217,318] (115,217] (13.7,115] (115,217] (217,318] (318,420]
> > >> [7] (217,318] (115,217] (115,217] (217,318] (318,420] (420,521]
> > >> [13] (420,521] (318,420] (217,318] (115,217] (115,217] (115,217]
> > >> [19] (217,318] (318,420] (217,318] (217,318] (217,318] (217,318]
> > >> [25] (217,318] (217,318] (318,420] (420,521] (420,521] (420,521]
> > >> [31] (318,420] (13.7,115]
> > >> Levels: (13.7,115] (115,217] (217,318] (318,420] (420,521]
> > >>
> > >>
> > >> I want then for the numbers of my initial vector that fall within the
> > >> same "category" lets say the (318,420] to be collected on a vector.I
> > >> rephrase it the indexes of my initial vector that have a value between
> > >> 318 to 420 to be put in a same vector that I can process then as I want.
> > >> How I can do that effectively in R?
> > >> I would like to thank you for your replyRegardsAlex
> > >>
> > >> [[alternative HTML version deleted]]
> > >>
> > >> ______________________________________________
> > >> R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
> > >> https://stat.ethz.ch/mailman/listinfo/r-help
> > >> PLEASE do read the posting guide
> > >> http://www.R-project.org/posting-guide.html
> > >> and provide commented, minimal, self-contained, reproducible code.
> > >
> > >
> > > [[alternative HTML version deleted]]
> > >
> > > ______________________________________________
> > > R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
> > > https://stat.ethz.ch/mailman/listinfo/r-help
> > > PLEASE do read the posting guide
> > > http://www.R-project.org/posting-guide.html
> > > and provide commented, minimal, self-contained, reproducible code.
> >
> >
>
>
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