Thanks it works great and gives me group numbers as integers and thus I can 
with which group the elements as needed (which (groups== 2))
Question though is how to keep also the labels for each group. For example that 
my first group is the [13,206)
RegardsAlex
 


     On Wednesday, November 4, 2015 1:00 PM, Boris Steipe 
<boris.ste...@utoronto.ca> wrote:
   

 I would transform the original numbers into integers which you can use as 
group labels. The row numbers of the group labels are the indexes of your 
values.

Example: assume your input vector is dBin

nGroups <- 5  # number of groups
groups <- (dBin - min(dBin)) / (max(dBin) - min(dBin)) # rescale to the range 
[0,1]
groups <- floor(groups * nGroups) + 1  # discretize to nGroups integers

Now you can eg. get the indices for group 2

groups[groups == 2]

Depending on the nature of your input data, it may be better to keep these 
groups in a column adjacent to your values, rather than in a separate vector, 
or even better to just calculate the groups on the fly in your downstream 
analysis with the approach given above in a function, rather than storing them 
at all. These are simple operations that should not add perceptibly to 
execution time.

Cheers,
Boris






On Nov 4, 2015, at 6:40 AM, Alaios via R-help <r-help@r-project.org> wrote:

> Thanks for the answer. Split does not give me the indexes though but only in 
> which group they fall in. I also need the index of the group. Is the first, 
> the second .. group?Alex
> 
> 
> 
>    On Tuesday, November 3, 2015 5:05 PM, Ista Zahn <istaz...@gmail.com> wrote:
> 
> 
> Probably
> 
> split(binDistance, test).
> 
> Best,
> Ista
> 
> On Tue, Nov 3, 2015 at 10:47 AM, Alaios via R-help <r-help@r-project.org> 
> wrote:
>> Dear all,I am not exactly sure on what is the proper name of what I am 
>> trying to do.
>> I have a vector that looks like
>>  binDistance
>>            [,1]
>>  [1,] 238.95162
>>  [2,] 143.08590
>>  [3,]  88.50923
>>  [4,] 177.67884
>>  [5,] 277.54116
>>  [6,] 342.94689
>>  [7,] 241.60905
>>  [8,] 177.81969
>>  [9,] 211.25559
>> [10,] 279.72702
>> [11,] 381.95738
>> [12,] 483.76363
>> [13,] 480.98841
>> [14,] 369.75241
>> [15,] 267.73650
>> [16,] 138.55959
>> [17,] 137.93181
>> [18,] 184.75200
>> [19,] 254.64359
>> [20,] 328.87785
>> [21,] 273.15577
>> [22,] 252.52830
>> [23,] 252.52830
>> [24,] 252.52830
>> [25,] 262.20084
>> [26,] 314.93064
>> [27,] 366.02996
>> [28,] 442.77467
>> [29,] 521.20323
>> [30,] 465.33071
>> [31,] 366.60582
>> [32,]  13.69540
>> so numbers that start from 13 and go up to maximum 522 (I have also many 
>> other similar sets).I want to put these numbers into 5 categories and thus I 
>> have tried cut
>> 
>> 
>> Browse[2]> 
>> test<-cut(binDistance,seq(min(binDistance)-0.00001,max(binDistance),length.out=scaleLength+1))
>> Browse[2]> test
>>  [1] (217,318]  (115,217]  (13.7,115] (115,217]  (217,318]  (318,420]
>>  [7] (217,318]  (115,217]  (115,217]  (217,318]  (318,420]  (420,521]
>> [13] (420,521]  (318,420]  (217,318]  (115,217]  (115,217]  (115,217]
>> [19] (217,318]  (318,420]  (217,318]  (217,318]  (217,318]  (217,318]
>> [25] (217,318]  (217,318]  (318,420]  (420,521]  (420,521]  (420,521]
>> [31] (318,420]  (13.7,115]
>> Levels: (13.7,115] (115,217] (217,318] (318,420] (420,521]
>> 
>> 
>> I want then for the numbers of my initial vector that fall within the same 
>> "category" lets say the (318,420] to be collected on a vector.I rephrase it 
>> the indexes of my initial vector that have a value between 318 to 420 to be 
>> put in a same vector that I can process then as I want.
>> How I can do that effectively in R?
>> I would like to thank you for your replyRegardsAlex
>> 
>>        [[alternative HTML version deleted]]
>> 
>> ______________________________________________
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>> and provide commented, minimal, self-contained, reproducible code.
> 
> 
>     [[alternative HTML version deleted]]
> 
> ______________________________________________
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