Thanks for the answer. Split does not give me the indexes though but only in
which group they fall in. I also need the index of the group. Is the first, the
second .. group?Alex
On Tuesday, November 3, 2015 5:05 PM, Ista Zahn <istaz...@gmail.com> wrote:
Probably
split(binDistance, test).
Best,
Ista
On Tue, Nov 3, 2015 at 10:47 AM, Alaios via R-help <r-help@r-project.org> wrote:
> Dear all,I am not exactly sure on what is the proper name of what I am trying
> to do.
> I have a vector that looks like
> binDistance
> [,1]
> [1,] 238.95162
> [2,] 143.08590
> [3,] 88.50923
> [4,] 177.67884
> [5,] 277.54116
> [6,] 342.94689
> [7,] 241.60905
> [8,] 177.81969
> [9,] 211.25559
> [10,] 279.72702
> [11,] 381.95738
> [12,] 483.76363
> [13,] 480.98841
> [14,] 369.75241
> [15,] 267.73650
> [16,] 138.55959
> [17,] 137.93181
> [18,] 184.75200
> [19,] 254.64359
> [20,] 328.87785
> [21,] 273.15577
> [22,] 252.52830
> [23,] 252.52830
> [24,] 252.52830
> [25,] 262.20084
> [26,] 314.93064
> [27,] 366.02996
> [28,] 442.77467
> [29,] 521.20323
> [30,] 465.33071
> [31,] 366.60582
> [32,] 13.69540
> so numbers that start from 13 and go up to maximum 522 (I have also many
> other similar sets).I want to put these numbers into 5 categories and thus I
> have tried cut
>
>
> Browse[2]>
> test<-cut(binDistance,seq(min(binDistance)-0.00001,max(binDistance),length.out=scaleLength+1))
> Browse[2]> test
> [1] (217,318] (115,217] (13.7,115] (115,217] (217,318] (318,420]
> [7] (217,318] (115,217] (115,217] (217,318] (318,420] (420,521]
> [13] (420,521] (318,420] (217,318] (115,217] (115,217] (115,217]
> [19] (217,318] (318,420] (217,318] (217,318] (217,318] (217,318]
> [25] (217,318] (217,318] (318,420] (420,521] (420,521] (420,521]
> [31] (318,420] (13.7,115]
> Levels: (13.7,115] (115,217] (217,318] (318,420] (420,521]
>
>
> I want then for the numbers of my initial vector that fall within the same
> "category" lets say the (318,420] to be collected on a vector.I rephrase it
> the indexes of my initial vector that have a value between 318 to 420 to be
> put in a same vector that I can process then as I want.
> How I can do that effectively in R?
> I would like to thank you for your replyRegardsAlex
>
> [[alternative HTML version deleted]]
>
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