Does the following not do what you want?
k1 <- c(0.005, 0.200, 0.300, 0.400, 0.500, 0.600, 0.700, 0.800, 0.900,
1.000, 1.100, 1.200, 1.300, 1.400, 1.500, 1.600, 1.700, 1.800,
1.900, 2.000, 5.000, 10.000)
k1
xr <- lapply(k1, rnorm, n=20)
xr
On Fri, Oct 23, 2015 at 1:51 AM, Erin Hodgess <erinm.hodg...@gmail.com> wrote:
> Hello!
>
> I would like to create a list of random values, based on various means.
> Here are the potential mean values:
>
>> k1
> [1] 0.005 0.200 0.300 0.400 0.500 0.600 0.700 0.800 0.900 1.000
> 1.100 1.200 1.300 1.400
> [15] 1.500 1.600 1.700 1.800 1.900 2.000 5.000 10.000
>
> There are 22 of them.
>
> My original thought was to use "do.call" to produce a list of 22 items of
> size 20.
>
>> xr <- do.call("rnorm",args=list(n=20,mean=k1))
>> xr
> [1] -1.46443269 0.83384389 0.39176720 -0.17954959 0.28245948
> -0.44148055 1.98009926 1.73881739
> [9] 1.37312454 1.40509257 -0.03762214 0.43636354 1.82175069
> 1.96439065 2.71731752 1.02388062
> [17] 1.20732047 3.08650964 0.87910868 0.13018727
>>
>
> However, I am just getting back one set of size 20. What am I doing wrong,
> please? Or do I need to do a loop, please? I thought that there must be a
> more elegant solution.
>
> This is on a Macbook Air, R version 3.2.2
>
> Thanks so much,
> Sincerely
>
> --
> Erin Hodgess
> Associate Professor
> Department of Mathematical and Statistics
> University of Houston - Downtown
> mailto: erinm.hodg...@gmail.com
>
> [[alternative HTML version deleted]]
>
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