Dear Rolf and Adams,
Thanks for your help! works perfectly.though all columns are of the same type,
for "safe", it is changed from data.frame to data.matrix as follows:
dmatrix <- data.matrix(dailyrecord[c("a", "e", "f")])
colnames(dmatrix) <- c("x5", "x6", "x7")
apply(dmatrix, 1, function(row) fun3(list1, list2, as.list(row)))
Thanks again!
Bests,LQ
From: Rolf Turner <r.tur...@auckland.ac.nz>
To: "Adams, Jean" <jvad...@usgs.gov>; liqun...@yahoo.com
Cc: "r-help@r-project.org" <r-help@r-project.org>
Sent: Friday, October 9, 2015 7:28 PM
Subject: Re: [FORGED] Re: [R] R lappy, sapply or mapply question
On 10/10/15 10:56, Adams, Jean wrote:
> You were very close. Try this.
>
> df <- data.frame(x5=dailyrecord$a, x6 = dailyrecord$e, x7 = dailyrecord$f)
> apply(df, 1, function(row) fun3(list1, list2, as.list(row)))
There could in general be problems with this approach. The apply()
function works on *matrices* and if handed a data frame coerces it to a
matrix. This is (usually!) OK if all columns of the data frame are of
the same type, but the world could end if they are not. It is a good
idea to *start* with a matrix if a matrix is what is required. And do
not confuse data frames with matrices. They are very different animals.
cheers,
Rolf Turner
--
Technical Editor ANZJS
Department of Statistics
University of Auckland
Phone: +64-9-373-7599 ext. 88276
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