FYI I did try something like this:
test = apply(test3,c(1,2),lmfunc,input=t)
but that gives me an array that is 10 rows by 5 columns by 5 slices, and I
need it to keep the same dimensions as test3 (5x5x10)
A
On Tue, Oct 6, 2015 at 1:42 PM, Adrienne Wootten <amwoo...@ncsu.edu> wrote:
> R-Helpers,
>
> I've seen some similar threads about this question online, but not quite
> what I'm looking for. I apologize in advance if someone's already answered
> this and I just can't find it online.
>
> Say that I have an array like test3 in the little example code I have
> below:
>
> test1 = array(rep(1:10,each = 25),dim=c(5,5,10))
> test2 = array(rnorm(250,0,0.35),dim=c(5,5,10))
> test3 = test1+test2 # array with 5 rows, 5 columns, 10 slices
>
> time=1:10
>
> Where the dimensions are x, y, and time. What I'd like to do is run a
> regression (for the sake of this example, say lm) on each x,y in time. So
> for a single cell the formula might be test3[1,1,]~time, but I'd like to
> that for all cells. The only way I can immediately think of is to use a
> loop, but I'm wondering if there's a way to do this without a loop.
> Perhaps with tapply?
>
> I'm actually doing a fourth order regression with a much larger array, but
> this simple example illustrates the question I have.
>
> Many thanks for the help! Sorry if someone's already answered this and I
> can't find it.
>
> Adrienne
>
> --
> Adrienne Wootten
> Graduate Research Assistant
> State Climate Office of North Carolina
> Department of Marine, Earth and Atmospheric Sciences
> North Carolina State University
>
--
Adrienne Wootten
Graduate Research Assistant
State Climate Office of North Carolina
Department of Marine, Earth and Atmospheric Sciences
North Carolina State University
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