On Sep 15, 2015, at 4:46 PM, David L Carlson wrote:
> I realize that you can break this approach as well with a suitably complex
> expression, but I took it as a challenge:
>
>> dat <- data.frame(ASB = c(LETTERS[1:3]), Flow=c(11.51, 9.2, 10.5),
>> stringsAsFactors=FALSE)
>> cat <- LETTERS[1:3]
>> mult <- c("'*'(2," , "'+'(5,", "sqrt(")
>> sapply(parse(text=paste0(mult[match(dat$ASB, cat)], dat$Flow, ")")), eval)
> [1] 23.02000 14.20000 3.24037
This seems a bit less tortured:
> mapply( function(x,y) switch(x, A=y*2, B=y+3, C=sqrt(y) ), dat$ASB, dat$Flow
> )
A B C
23.02000 12.20000 3.24037
Best;
The Other David
>
> David
>
> -----Original Message-----
> From: Bert Gunter [mailto:bgunter.4...@gmail.com]
> Sent: Tuesday, September 15, 2015 4:43 PM
> To: David L Carlson <dcarl...@tamu.edu>
> Cc: Peter Alspach <peter.alsp...@plantandfood.co.nz>; r-help@r-project.org
> Subject: Re: [R] Multiple if function
>
> Thanks, David.
>
> I would say, not quite.
>
> What if the alternatives are:
>
> If class = "a" multiply y by 2;
> If class = "b" add 5 to y;
> If class = "c" take sqrt(y)
> (where y is numeric, say)
> ?
>
> Cheers,
> Bert
> Bert Gunter
>
> "Data is not information. Information is not knowledge. And knowledge
> is certainly not wisdom."
> -- Clifford Stoll
>
>
> On Tue, Sep 15, 2015 at 2:11 PM, David L Carlson <dcarl...@tamu.edu> wrote:
>> You could use match() and avoid ifelse():
>>
>>> dat <- data.frame(ASB = c(LETTERS[1:3]), Flow=c(11.51, 9.2, 10.5),
>>> stringsAsFactors=FALSE)
>>> cat <- LETTERS[1:3]
>>> mult <- c(.1, .15, .2)
>>> dat$Flow * mult[match(dat$ASB, cat)]
>> [1] 1.151 1.380 2.100
>>
>> -------------------------------------
>> David L Carlson
>> Department of Anthropology
>> Texas A&M University
>> College Station, TX 77840-4352
>>
>>
>> -----Original Message-----
>> From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of Bert Gunter
>> Sent: Tuesday, September 15, 2015 3:51 PM
>> To: Peter Alspach
>> Cc: r-help@r-project.org
>> Subject: Re: [R] Multiple if function
>>
>> ... but this only works if ASBclass is numeric. What if it is a factor
>> (or even character)?
>>
>> One can always finesse factors in simple cases like this, but for 2
>> reasons, I don't think it's a good idea.
>>
>> 1. One should make use of a factor's API, rather than its internal
>> integer representation(which, I grant, ain't likely to change);
>>
>> 2. For more complicated alternatives (e.g. entirely different
>> functions depending on the factor value) it won't work anyway.
>>
>> For simple cases, ifelse() seems reasonable; but for more alternatives
>> -- say 10 or 50 -- this becomes too cumbersome (imho). I think the
>> split and recombine approach then becomes the best option, but maybe
>> there is some easier, shorter, approach that I am overlooking. Please
>> correct me if this is the case.
>>
>> Best,
>> Bert
>>
>>
>>
>>
>>
>>
>> Bert Gunter
>>
>> "Data is not information. Information is not knowledge. And knowledge
>> is certainly not wisdom."
>> -- Clifford Stoll
>>
>>
>> On Tue, Sep 15, 2015 at 12:23 PM, Peter Alspach
>> <peter.alsp...@plantandfood.co.nz> wrote:
>>> Tena koe Maria
>>>
>>> It seems you need to multiply Flow by 0.05+ASBClass/20 (i.e., no if calls
>>> are necessary)
>>>
>>> HTH ....
>>>
>>> Peter Alspach
>>>
>>> -----Original Message-----
>>> From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of Maria
>>> Lathouri
>>> Sent: Tuesday, 15 September 2015 10:57 p.m.
>>> To: r-help@r-project.org
>>> Subject: [R] Multiple if function
>>>
>>> Dear all,
>>>
>>> I am writing as I would like your help. I have a dataframe with two
>>> columns, ASB and Flow, where the the first one has values 1, 2 or 3 and the
>>> second flow data. Something like that:
>>> ASBclass Flow1 11.51 9.2
>>> 2 10.5
>>> 3 6.7 ... ...
>>> I would like to produce a third column named eg. deviation where it would
>>> get me values based on if ASBclass is 1, multiply Flow by 0.1; if ASBclass
>>> is 2 then multiply Flow by 0.15 and if ASBclass is 3 then multiply by 0.2.
>>>
>>> If (ASBclass=1) { deviation<-Flow*0.1}
>>> If (ASBclass=2) { deviation<-Flow*0.15}If (ASBclass=1) {
>>> deviation<-Flow*0.2} I am not sure whether I should add the else function
>>> and how can I combine these separate functions.
>>>
>>> Can anyone help me on that?
>>> Thank you very much.
>>>
>>> Kind regardsMaria
>>>
>>> [[alternative HTML version deleted]]
>>>
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>>
>> ______________________________________________
>> R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
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>> and provide commented, minimal, self-contained, reproducible code.
> ______________________________________________
> R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
David Winsemius
Alameda, CA, USA
______________________________________________
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
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