Hi OK, thanks for sending dput result.
I am still not sure what exactly you want. Using ?ave you can get result of x/max(x) dat$prob <- ave(dat$value, paste(dat$id, dat$i), FUN= function(x) x/max(x)) however in case max(x) is zero the result is NA You can change it to zero dat$prob[is.nan(dat$prob)] <- 0 and compute rank value by similar process. dat$rankvalue <- ave(dat$prob, paste(dat$id, dat$i), FUN = rank) But I am not sure if this is the desired result. Cheers Petr > -----Original Message----- > From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of Ragia > Ibrahim > Sent: Monday, September 07, 2015 10:12 AM > To: Sarah Goslee; r-help@r-project.org > Subject: Re: [R] groups Rank > > apology for re sending the Email, I changed the format to plain text as > I have been advised the data is as follow > > thanks Sarah, > I used pdut, and here is the data as written on R..I attached the dput > result structure(list(Measure_id = c(1, 1, 1, 1, 1, 2, 2, 2, 3, 3, 3, > 3, 1, 1, 1, 1, 1, 2, 2, 2, 3, 3, 3, 3, 1, 1, 1, 1, 1, 2, 2, 2, 3, 3, 3, > 3, 1, 1, 1, 1, 1, 2, 2, 2, 3, 3, 3, 3), i = c(5, 5, 5, 5, 5, 5, 5, 5, > 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 7, 7, 7, 7, 7, 7, 7, 7, > 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7), j = c(1, 1, 1, 1, 1, > 1, 1, 1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 3, 3, 3, 3, 3, > 3, 3, 3, 3, 3, 3, 3, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5), id = c(1, 2, > 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, > 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, > 11, 12), value = c(2, 1.5, 0, 0, 1, 0.5, 0, 0, 0, 0, 0.5, 2, 2, 1.5, 0, > 1, 2, 0, 0.5, 1.44269504088896, 0, 0, 0, 0, 1, 1.5, 0, 0, 1, 0, 0, 0, > 0, 0, 0, 0, 1, 2, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0)), .Names = > c("Measure_id", "i", "j", "id", "value"), row.names = c(NA, 48L), class > = "data.frame") > > the data is as follow : > > Measure_id i j id value > 1 1 5 1 1 2.0 > 2 1 5 2 1 2.0 > 3 1 5 1 2 1.5 > 4 1 5 2 2 1.5 > 5 1 5 1 3 0.0 > 6 1 5 2 3 0.0 > 7 1 5 1 4 0.0 > 8 1 5 2 4 1.0 > 9 1 5 1 5 1.0 > 10 1 5 2 5 2.0 > .. ... . . .. ... > I want to add a probability column, the prob column depends on id > grouped by for each i the rank will be current (value / max value ) for > the same id for specific i, it would be > > Measure_id i j id value prob > 1 1 5 1 1 2.0 2/2 > 2 1 5 2 1 2.0 2/2 > 3 1 5 1 2 1.5 1.5/1.5 > 4 1 5 2 2 1.5 1.5/1.5 > 5 1 5 1 3 0.0 0 > 6 1 5 2 3 0.0 0 > 7 1 5 1 4 0.0 0/1 > 8 1 5 2 4 1.0 1/1 > 9 1 5 1 5 1.0 1/2 > 10 1 5 2 5 2.0 2/3 > .. ... . . .. ... > > then I want to add a rank column that rank regarding probability, if > the probability equal they took the same rank for the same id belongs > to the same i, otherwize lower probability took higher rank for examole > if we have three values for i=7 and for the three values the id is 1 > and the probability is ( .2,.4,.5) the rank should be 3,2,1 > > > > I looked at aggregate and dplyr...should I use for loop and subset each > i and id rows do calculations and then group them again ?? > is there easier way? > > replying highly appreciated > > > > > > > >> Date: Sun, 6 Sep 2015 19:02:02 -0400 > >> Subject: Re: [R] groups Rank > >> From: sarah.gos...@gmail.com > >> To: ragi...@hotmail.com > >> CC: r-help@r-project.org > >> > >> Please use dput() to provide data, rather than expecting people to > >> open random attachments. Besides, there are multiple options for > >> getting data into R, and we need to know exactly what you did. > dput() > >> is faster and easier. > >> > >> What have you tried? Did you look at aggregate() as I suggested? > >> > >> Sarah > >> > >> On Sat, Sep 5, 2015 at 10:44 AM, Ragia Ibrahim <ragi...@hotmail.com> > wrote: > >>> thanks for replying, I attached the data frame for source "i" I > want > >>> to sum the values and get the max value then add a new column > called > >>> rank . That new column cell value for each source i and for > specific > >>> id would be (value/max value) * count of rows that have the same > >>> criteria "same i and same id" > >>> > >>> many thanks > >>> Ragia > >>> > >>>> Date: Fri, 4 Sep 2015 10:19:35 -0400 > >>>> Subject: Re: [R] groups Rank > >>>> From: sarah.gos...@gmail.com > >>>> To: ragi...@hotmail.com > >>>> CC: r-help@r-project.org > >>>> > >>>> Hi Ragia, > >>>> > >>>> I can't make out your data or desired result, but it sounds like > >>>> aggregate() might get you started. If you need more help, please > >>>> repost your data using dput() and do NOT post in HTML so that we > >>>> can see what your desired result looks like. > >>>> > >>>> Sarah > >>>> > >>>> On Fri, Sep 4, 2015 at 10:12 AM, Ragia Ibrahim > >>>> <ragi...@hotmail.com> > >>>> wrote: > >>>>> Dear Group,kinldy, I have the following data frame df id value1 1 > >>>>> 4 2 1 4 3 1 6 4 1 6 5 2 1.5 6 2 2.5 7 2 2.5 8 2 2.5 > >>>>> > >>>>> add rank column regarding id coulmn where rank for the highest > >>>>> value would be 1, others rank would be the (value/ value of > >>>>> heighest)/ > > number of > >>>>> rows that took the same value > >>>>> thus the data frame should be > >>>>> id value Rank1 1 4 0.332 1 4 0.333 1 6 0.54 1 6 0.55 2 1.5 0.6 6 > 2 > >>>>> 2.5 > >>>>> 0.337 2 2.5 0.338 2 2.5 0.33 > >>>>> > >>>>> how to reach this resultthanks in advanceRagia [[alternative HTML > >>>>> version deleted]] > >>>>> > > ______________________________________________ > R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting- > guide.html > and provide commented, minimal, self-contained, reproducible code. ________________________________ Tento e-mail a jakékoliv k němu připojené dokumenty jsou důvěrné a jsou určeny pouze jeho adresátům. 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