Dear all,
I need your urgent help J
I’m naïve, and I’m pretty sure my doubt is very simple to solve, but I’m not
getting it.
I used the following code to produce my research graphs, nonetheless, is this
problem, I do not have 6 graphs (1 – 6),
# 3 4 5
# 2
# 6 7 8
but only 4,instead. So, I need to reformulate the code, just to
# 3 4
# 2
# 6 7
Can you please help me reformulating?
I suppose I have to change something in the split.screen code, because
nowadays, my “third” column is blank J
I attach the code:
library(ggplot2)
library(reshape)
library(lattice)
mean.alpha1<-read.csv("graphs_mean_alpha1.csv")
mean.alpha2<-read.csv("graphs_mean_alpha2.csv")
quartz(width=10,height=5)
split.screen(figs=matrix(c(0,0.4,0.5,1,
0.4,0.7,0.5,1,
0.7,1,0.5,1,
0,0.4,0,0.5,
0.4,0.7,0,0.5,
0.7,1,0,0.5),nrow=6,byrow=TRUE),
screen=1)
screen(3)
par(mar=c(0,3.5,3,0))
# now the second set
n250<-mean.alpha1$nsample==250
matplot(x=mean.alpha1$lambda[n250],y=mean.alpha1[n250,3:5],
type="l",pch=1:3,col=c(4,2,3),xaxt="n",ylim=c(-1.2,
-0.25),main="nsample=250",ylab="", cex.main=1)
abline(h = -1, col = "gray60")
mtext(expression(paste("mean av. for ",alpha[1])),side=2,line=2, cex.main=1)
screen(4)
par(mar=c(0,0,3,0))
# now the second set
n250<-mean.alpha1$nsample==1000
matplot(x=mean.alpha1$lambda[n1000],y=mean.alpha2[n1000,3:5],
type="l",pch=1:3,col=c(4,2,3),xaxt="n",yaxt="n",ylim=c(-1.2,
-0.25),main="nsample=1000", cex.main=1)
abline(h = -1, col = "gray60")
screen(6)
par(mar=c(3,3.5,0,0))
# now the second set
n250<-mean.alpha2$nsample==250
matplot(x=mean.alpha2$lambda[n250],y=mean.alpha2[n250,3:5],
type="l",pch=1:3,col=c(4,2,3),ylim=c(-.6, -.35),ylab="")
abline(h = -.5, col = "gray60")
mtext(expression(paste(lambda)),side=1,line=2, cex.main=1.5)
mtext(expression(paste("mean av. for ",alpha[2])),side=2,line=2, cex.main=1.5)
screen(7)
par(mar=c(3,0,0,0))
# now the second set
n1000<-mean.alpha2$nsample==1000
matplot(x=mean.alpha2$lambda[n1000],y=mean.alpha2[n1000,3:5],
type="l",pch=1:3,col=c(4,2,3),yaxt="n",ylim=c(-.6, -.35))
abline(h = -.5, col = "gray60")
mtext(expression(paste(lambda)),side=1,line=2, , cex.main=1.5)
screen(2)
par(mar=c(0,0,0,0))
# plot an empty plot to get the coordinates
plot(0:1,0:1,type="n",axes=FALSE)
legend(0,0.6,c("OLS", "GLS", "Reg. Cal.", "true coefficient"),bty = "n",
lty=1:3,col=c(4,2,3,"gray60"),xpd=TRUE)
close.screen(all=TRUE)
BEST,
RO
Atenciosamente,
Rosa Oliveira
--
____________________________________________________________________________
Rosa Celeste dos Santos Oliveira,
E-mail: rosit...@gmail.com
Tlm: +351 939355143
Linkedin: https://pt.linkedin.com/in/rosacsoliveira
____________________________________________________________________________
"Many admire, few know"
Hippocrates
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