Yes, correct, thank you, Bert! On Mon, Jul 27, 2015 at 5:46 PM, Bert Gunter <bgunter.4...@gmail.com> wrote: > No it wouldn't. > > Presumably you have a typo and meant > > rk <- c(2,4,3,1,NA) > > ## and set the (5,5) entry to 0 after > > -- Bert > > > Bert Gunter > > "Data is not information. Information is not knowledge. And knowledge > is certainly not wisdom." > -- Clifford Stoll > > > On Mon, Jul 27, 2015 at 2:32 PM, Dimitri Liakhovitski > <dimitri.liakhovit...@gmail.com> wrote: >> With NAs it'd be: >> >> rk <- c(2,NA,4,3,1, NA) >> outer(rk, rk, "<") + 0 >> >> Wow, I still can't believe it - just one line! >> >> >> On Mon, Jul 27, 2015 at 5:31 PM, Dimitri Liakhovitski >> <dimitri.liakhovit...@gmail.com> wrote: >>> Wow! >>> >>> On Mon, Jul 27, 2015 at 5:28 PM, Bert Gunter <bgunter.4...@gmail.com> wrote: >>>> ## I leave it to you to add the NA edges >>>> >>>>> rk <- c(2,4,3,1) >>>> >>>>> outer(rk,rk,"<")+0 >>>> >>>> [,1] [,2] [,3] [,4] >>>> [1,] 0 1 1 0 >>>> [2,] 0 0 0 0 >>>> [3,] 0 1 0 0 >>>> [4,] 1 1 1 0 >>>> >>>> >>>> >>>> Cheers, >>>> Bert >>>> >>>> Bert Gunter >>>> >>>> "Data is not information. Information is not knowledge. And knowledge >>>> is certainly not wisdom." >>>> -- Clifford Stoll >>>> >>>> >>>> On Mon, Jul 27, 2015 at 12:38 PM, Dimitri Liakhovitski >>>> <dimitri.liakhovit...@gmail.com> wrote: >>>>> I have 5 items in total (1:5), but I show a person only 4 items (1:4) >>>>> and ask this person to rank items 1:4 in terms of preferences (1 is >>>>> best, 2 is second best, 4 is worst), and I get a vector of ranks: >>>>> ranks <- c(2,4,3,1) >>>>> >>>>> # That means that this person liked item 4 best and item 2 worst. >>>>> >>>>> I would like to "unfirl" this vector of ranks into a matrix of >>>>> preferences where if the row item prefers the column item, then it's a >>>>> 1. Otherwise, it's a zero. So, the output should be a 5 by 5 matrix >>>>> (because overall we have 5 items, not 4, but item 5 did not >>>>> participate in rankings), and it would always have zeros in a >>>>> diagonal.: >>>>> >>>>> 0 1 1 0 NA >>>>> 0 0 0 0 NA >>>>> 0 1 0 0 NA >>>>> 1 1 1 0 NA >>>>> NA NA NA NA 0 >>>>> >>>>> I can loop through all possible pairs the person saw and fill the >>>>> matrix accordingly, but it seems like a lot of looping. Could one do >>>>> it in a more elegant way? >>>>> >>>>> Thank you very much! >>>>> >>>>> >>>>> -- >>>>> Dimitri Liakhovitski >>>>> >>>>> ______________________________________________ >>>>> R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see >>>>> https://stat.ethz.ch/mailman/listinfo/r-help >>>>> PLEASE do read the posting guide >>>>> http://www.R-project.org/posting-guide.html >>>>> and provide commented, minimal, self-contained, reproducible code. >>> >>> >>> >>> -- >>> Dimitri Liakhovitski >> >> >> >> -- >> Dimitri Liakhovitski
-- Dimitri Liakhovitski ______________________________________________ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
