On Jun 25, 2015, at 1:25 PM, Dimitri Liakhovitski wrote:
> Hello!
>
> I have a data frame md:
>
> md <- data.frame(x = c(3,5,4,5,3,5), y = c(5,5,5,4,4,1), z =
> c(1,3,4,3,5,5),
> device1 = c("c","a","a","b","c","c"), device2 =
> c("B","A","A","A","B","B"))
> md[2,3] <- NA
> md[4,1] <- NA
> md
>
> I want to calculate means by device1 / device2 combinations using dplyr:
>
> library(dplyr)
> md %>% group_by(device1, device2) %>% summarise_each(funs(mean))
>
> However, I am getting some NAs. I want the NAs to be ignored (na.rm =
> TRUE) - I tried, but the function doesn't want to accept this
> argument.
The help page for the `funs`-function has several examples:
This succeeds:
md %>% group_by(device1, device2) %>% summarise_each(funs(mean( .,
na.rm=TRUE))))
> Both these lines result in error:
>
> md %>% group_by(device1, device2) %>% summarise_each(funs(mean),
> na.rm = TRUE)
> md %>% group_by(device1, device2) %>% summarise_each(funs(mean,
> na.rm = TRUE))
>
> Thank you for your advice!
>
>
> --
> Dimitri Liakhovitski
>
> ______________________________________________
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> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
David Winsemius
Alameda, CA, USA
______________________________________________
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
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