Oh, Swami, gazing into the crystal ball one can see ...
;-}
Cheers,
Bert
Bert Gunter
"Data is not information. Information is not knowledge. And knowledge is
certainly not wisdom."
-- Clifford Stoll
On Thu, Jun 11, 2015 at 4:48 PM, David Winsemius <dwinsem...@comcast.net>
wrote:
>
> On Jun 11, 2015, at 12:25 PM, Kevin Kowitski wrote:
>
> > Hey,
> >
> > I am having an issue with a for loop that is intended to read index
> values by row and column so that it can pull out the valuable information.
> My issue is that I am using a data.frame(which(df==1, arr.ind=TRUE))
>
> That would be coercing a matrix to a dataframe. But why?
>
>
> > to find the index of the values in my data frame that are equal to 1.
> This outputs a data frame of 71 rows which is confirmed by the "nrows"
> function. However, when I try to break up the rows and columns using the
> code below I am producing two vectors of 75 values, even though there are
> only 71 and the for loop is from 1 to the value of 71. Am I making this
> task more complicated than it needs to be?
> >
> > if(countRaw > 0){
>
> How the value of countRow enters into this is entirely unclear.
>
> > index_R_df<-rbind( index_R_df,
> data.frame(which(sapply(data2[0:24,],
>
> R does NOT use zero-based indexing.
>
>
> > match, INDString, nomatch=0)==1, arr.ind=TRUE)))
>
> You need to explain what you are doing here. It's a bit too obscure to me
> how we should know that index_R_df will line up with the items would drop
> out of:
>
> data.frame(which(sapply(data2[0:24,],match, INDString, nomatch=0)==1,
> arr.ind=TRUE)))
>
> I would have expected some `name` to be followed by `[` then `which(...)`
>
>
> > index_lengthR<-nrow(index_R_df)
> >
> > for (j in 1:index_lengthR){
> > index_rowsR<-c(index_rowsR,
> index_R_df[j,1])
> > index_colsR<-c(index_colsR,
> index_R_df[j,2])
> > #rowsPass_R<-c(unique(index_rowsR))
> > #collect_rows<-c(collect_rows,
> rowsPass_R)
> > }
> >
>
> There are too many missing here for me to do anything useful. You are
> either only giving us a fragment of code and using zero based indexing.
> Without a data example, I'm throwing it back to you ot someone in the
> readership with better intuition or imagination than I possess.
>
>
> > I'm sorry if this seems very novice, I'm new to R.
> >
> > -Kevin
> > ______________________________________________
> > R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
> > https://stat.ethz.ch/mailman/listinfo/r-help
> > PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> > and provide commented, minimal, self-contained, reproducible code.
>
> David Winsemius
> Alameda, CA, USA
>
> ______________________________________________
> R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
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