You can use labels=as.expression(lapply(1:9, function(i)bquote(hat(lambda)[.(i)])))
Bill Dunlap TIBCO Software wdunlap tibco.com On Wed, Jun 3, 2015 at 12:39 PM, Frank S. <[email protected]> wrote: > Hi everyone, I have allocated greek letters with subscript numbers on > x-axis of my R plot this way: > plot(10:18, 30:38, lwd=2, xlim=c(10,18), ylim=c(30,38), xaxt="n", > xlab="weights", ylab="value") > points(10:18, 30:38, pch=19) > axis(1, at=10:18, labels=c(expression(hat(lambda)[1]), > expression(hat(lambda)[2]), expression(hat(lambda)[3]), > > expression(hat(lambda)[4]),expression(hat(lambda)[5]),expression(hat(lambda)[6]), > > expression(hat(lambda)[7]),expression(hat(lambda)[8]),expression(hat(lambda)[9])), > padj = 0.25) However, as you see in the last lines, it's not an efficient > code. I think it could be done more efficiently with a loop. I've searched > about this question and I've found some very similar question, but the > given answer does not work (with do.call and lapply). Maybe another > functions like substitute or parse. Does anybody can help me? Thanks a > bunch!! Frank S. > [[alternative HTML version deleted]] > > ______________________________________________ > [email protected] mailing list -- To UNSUBSCRIBE and more, see > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > [[alternative HTML version deleted]] ______________________________________________ [email protected] mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
