Hi Pijush, Without access to the data, we can only guess. However, in such cases the problem is often a factor variable where you expect a numeric one. Try this:
is.factor(x) and if the answer is TRUE, you have found your problem. Jim On Wed, Jun 3, 2015 at 4:13 PM, Pijush Das <topij...@gmail.com> wrote: > Dear Sir, > > I am facing an error when I am trying to use svm and found similar kind of > problem faced by other. But I unable to solve the problem. The problem is > given below. > >> rm(list=ls(all=TRUE)) >> CombinedGeneList <- read.xlsx(file.choose(), sheet = 1, colNames = > TRUE,rowNames = TRUE) >> NoemalisedData <- read.xlsx(file.choose(), sheet=1,colNames = > TRUE,rowNames = TRUE) >> status<-NoemalisedData[1, ] >> FilterData <-NoemalisedData[rownames(CombinedGeneList), ] >> TFilterData <- t(FilterData) >> Tstatus <- t(status) >> x<-TFilterData >> y<-Tstatus >> model <- svm( x, y) > Error in colMeans(x, na.rm = TRUE) : 'x' must be numeric >> > > > > Please solve the problem. I have tried it in many ways. > Waiting for your reply. > Thank you > > > > With regards > Pijush > > [[alternative HTML version deleted]] > > ______________________________________________ > R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. ______________________________________________ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
