Hi Kate,
I found that matching the character vector to itself is a very
effective way to do this:
x <- c("a", "bunch", "of", "strings", "whose", "exact", "content",
"is", "of", "little", "interest")
ids <- match(x, x)
ids
# [1] 1 2 3 4 5 6 7 8 3 10 11
By using this trick, many manipulations on character vectors can
be replaced by manipulations on integer vectors, which are sometimes
way more efficient.
Cheers,
H.
On 05/29/2015 09:58 AM, Kate Ignatius wrote:
I have a pedigree file as so:
X0001 BYX859 0 0 2 1 BYX859
X0001 BYX894 0 0 1 1 BYX894
X0001 BYX862 BYX894 BYX859 2 2 BYX862
X0001 BYX863 BYX894 BYX859 2 2 BYX863
X0001 BYX864 BYX894 BYX859 2 2 BYX864
X0001 BYX865 BYX894 BYX859 2 2 BYX865
And I was hoping to change all unique string values to numbers.
That is:
BYX859 = 1
BYX894 = 2
BYX862 = 3
BYX863 = 4
BYX864 = 5
BYX865 = 6
But only in columns 2 - 4. Essentially I would like the data to look like this:
X0001 1 0 0 2 1 BYX859
X0001 2 0 0 1 1 BYX894
X0001 3 2 1 2 2 BYX862
X0001 4 2 1 2 2 BYX863
X0001 5 2 1 2 2 BYX864
X0001 6 2 1 2 2 BYX865
Is this possible with factors?
Thanks!
K.
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--
Hervé Pagès
Program in Computational Biology
Division of Public Health Sciences
Fred Hutchinson Cancer Research Center
1100 Fairview Ave. N, M1-B514
P.O. Box 19024
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E-mail: hpa...@fredhutch.org
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______________________________________________
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
