Try gexp.arr <- data.matrix(gexp, rownames.force = FALSE) You are still supposed to get a matrix with one row (not a vector - dim(gexp.arr) is c(1,8) and not NULL).
--- On Thu, 12/6/08, Gundala Viswanath <[EMAIL PROTECTED]> wrote: > From: Gundala Viswanath <[EMAIL PROTECTED]> > Subject: [R] Data.matrix fail to convert data.frame into matrix > To: [EMAIL PROTECTED] > Received: Thursday, 12 June, 2008, 1:28 PM > Hi, > > With the following codes, I attempt to convert > the data.frame into a matrix. > > However I notice that data.matrix function doesn't > seem to work. > > __ BEGIN__ > dat <- read.table("mydata", comment.char = > "!" , na.strings = "null"); > # Select n-genes by random sample > # n = 1 > nosamp <- 1 > geneid <- sequence(nrow(dat)) > geneid.samp <- sample(geneid,nosamp) > geneid.samp > > gexp<- dat[geneid.samp,] > gexp.arr <- data.matrix(gexp, rownames.force = NA) > print(is.matrix(gexp.arr)) > print(gexp.arr) > > __END__ > > Yielding this output: > > __BEGIN__ > > print(is.matrix(gexp.arr)) > [1] TRUE > > print(gexp.arr) > V1 V2 V3 V4 V5 V6 V7 V8 > 10354 803.1 1107.8 431.6 349.8 386.7 646.3 744.2 620.9 > __END__ > > I expect "gexp.arr" to be a plain vector > (numeric). > What's wrong with my code above? > > > > > > -- > Gundala Viswanath > Jakarta-Indonesia > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, > reproducible code. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.