Use order(), as in
sortListByMean <- function(List) {
List[order(vapply(List, mean, 0))]
}
sortedL <- sortListByMean(l)
Bill Dunlap
TIBCO Software
wdunlap tibco.com
On Tue, Mar 3, 2015 at 11:01 AM, <mtb...@gmail.com> wrote:
> Hello R-helpers,
>
> I have a list of 999 dataframes and I would like to sort the list by the
> mean value of one of the columns in the data frames.
>
> Here is a small, self-contained example:
>
>
> #begin example
>
> iterations<-999
>
> d<-list() #resampled data
>
> f<-list() #fitted values
>
> r<-list() #residuals
>
> l<-list()
>
> for (i in 1:iterations){
>
> iboot<-sample(1:nrow(cars),replace=TRUE)
>
> bootdata<-cars[iboot,]
>
> d[[i]]<-bootdata
>
> f[[i]]<-fitted(lm(bootdata$dist~bootdata$speed))
>
> r[[i]]<-resid(lm(bootdata$dist~bootdata$speed))
>
> t<-data.frame(d[i],f[i],r[i]);names(t)<-c("speed","dist","fitted","resid")
>
> l[[i]]<-t
>
> } #end loop
>
> #end example
>
>
> Now, I would like to sort the 999 elements in this list by the mean value
> of the column named "fitted".
>
>
> In other words, the list element with the smallest mean value of "fitted"
> would be the new first list element, the list element with the second
> smallest mean value of "fitted" would be second new list element, etc....up
> to the list element with the largest mean value of "fitted".
>
>
> Thank you for any help you can provide!
>
>
> Best wishes, Mark
>
> [[alternative HTML version deleted]]
>
> ______________________________________________
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> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
[[alternative HTML version deleted]]
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